Jennifer scores a 77 on her algebra 2 test. The mean on the test was 73. The standard deviation on the test was 5. What was her
Z-score
1 answer:
Answer:
0.80
Step-by-step explanation:
The z-score is found from the formula ...
Z = (X -μ)/σ
Z = (77 -73)/5 = 4/5 = 0.80
Jennifer's Z-score was 0.80.
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