She would have 6 or 7 lessons 130 divided by 20 = 6.5
Answer:
See below ~
Step-by-step explanation:
Given :
<u>QRSTU ~ FGCDE</u>
Finding the scale factor :
- Take two corresponding sides in proportion
- RS : GC
- 40 : 12
- <u>10 : 3</u>
Applying the scale factor to find the missing sides :
- FG :
- QR : FG = 10 : 3
- 30/FG = 10/3
- FG = 30/10 x 3
- FG = 3 x 3
- <u>FG = 9</u>
- CD :
- ST : CD = 10 : 3
- 40/CD = 10/3
- CD = 40/10 x 3
- CD = 4 x 3
- <u>CD = 12</u>
- EF :
- UQ : EF = 10 : 3
- 30/EF = 10/3
- EF = 30/10 x 3
- EF = 3 x 3
- <u>EF = 9</u>
Answer: Skew lines are two lines that do not intersect and are not parallel. A simple example of a pair of skew lines is the pair of lines through opposite edges of a regular tetrahedron.
Answer:
60 seconds, 7715 feet
Step-by-step explanation:
Plane A and B start out 615 feet apart, and we find this by subtracting the height of plane A from plane B, getting 5000-4385=615. Now we have to find how many more feet of altitude plane A is gaining per second over plane B.
To find this we subtract 45.25 from 55.5 and get 10.25 feet per second. Now to find out how many seconds until they'll be at the same altitude we simply divide 615 by 10.25, getting 60 seconds.
For the second part, to find the altitude at this point, we simply multiply the altitude gain of one of the planes per second by the time of 60 seconds to get how much altitude they gained over that time, and add it to the starting altitude. Doing this with plane B we get 45.25*60=2715, and we add that to 5000 to get the final answer of 7715.
