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gtnhenbr [62]
3 years ago
8

Please help me with this question. It’s urgent.

Mathematics
1 answer:
dybincka [34]3 years ago
8 0

Answer:

C

Step-by-step explanation:

3-3=0

3-2=1

3-1=2

3-0=3

You can find the square root of these numbers. Even if you substituted a negative number in for x you can still find the square root of the number.

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3. The backyard of a home is a rectangle 25m by 30m. A garden of uniform width is to be
KiRa [710]

Answer:

Part A

The width of the garden is approximately 3.987 meters

Part B

Please find attached the drawing of the solution

Step-by-step explanation:

Part A

The given parameters are;

The dimensions of the backyard of the home = 25 m by 30 m

The width of the garden to be built in the yard = Uniform width

The shape of the grass left inside = Rectangular

The area of the grass at the center = The area of the garden

Let 'x' represent the width of the garden, we have;

The length of the rectangular grass area at the center, l = 30 - 2·x

The width of the rectangular area of grass at the center, w = 25 - 2·x

The area of the rectangular backyard, A = 30 m × 25 m = 750 m²

The area of the rectangular backyard, A = (The area of the garden) + (The area of the rectangle of grass inside)

The area of the rectangle of grass, GA = (30 - 2·x)·(25 - 2·x) = The area of the garden

The area of the rectangular backyard, A = 750 = (30 - 2·x)·(25 - 2·x) + (30 - 2·x)·(25 - 2·x)  = 2 × (30 - 2·x)·(25 - 2·x) = 8·x² - 220·x + 1,500

∴ 750 = 8·x² - 220·x + 1,500

8·x² - 220·x + 1,500 - 750 = 0

8·x² - 220·x + 750 = 0

x = (220 ± √(220² - 4 × 8 × 750))/(2 × 8)

x ≈ 23.513, or x = 3.987

When x = 25.513, the width of the rectangle of grass inside, w = 25 - 2 × 23.513 = -22.026, which is not a natural (physically possible)

Therefore, the possible width of the garden, x ≈ 3.987

Part B

The drawing of the solution created with MS Visio is attached

6 0
3 years ago
What is the volume of the composite figure? Express the
Papessa [141]

Answer:

V=312\pi\ mm^{3}

Step-by-step explanation:

we know that

The volume of the composite figure is equal to the volume of a semi-sphere plus the volume of the cone

so

V=\frac{4}{6}\pi r^{3} +\frac{1}{3} \pi r^{2} h

we have

r=6\ mm

h=14\ mm

substitute

V=\frac{4}{6}\pi (6)^{3} +\frac{1}{3} \pi (6)^{2} (14)

V=144\pi +168\pi

V=312\pi\ mm^{3}

3 0
3 years ago
Read 2 more answers
PLZ HURRY IT'S URGENT!
const2013 [10]

I = prt

To solve for r divide both sides by p and t.

r = I /pt

6 0
4 years ago
A book publishing company is shipping an order of 300 books.the books are packaged in boxes that each can hold 24 books.how many
ryzh [129]

300/24=12 your answer would be 12


4 0
4 years ago
A field with an area of 2880 ft^2 has the shape of a rectangle, whose length is 12 ft larger than its width. Find the dimensions
tiny-mole [99]

ANSWER

w=48,l=60

EXPLANATION

Let the width of the field be, w , then,

the length of the field will be:

l = 12 + w

The area of a rectangle is

Area = lw

This implies that:

w(12 + w) = 2880

Expand

{w}^{2}  + 12w = 2880

{w}^{2}  + 12w  -  2880 = 0

(x + 60)(x - 48) = 0

This implies that,

w =  - 60 \: w = 48

The dimensions are positive, the width is 48 and the length is 12+48=60

8 0
3 years ago
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