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Andre45 [30]
4 years ago
5

One tablespoon of peanut butter has a mass of 15 g . It is combusted in a calorimeter whose heat capacity is 120 kJ/∘C . The tem

perature of the calorimeter rises from 22.4 ∘C to 25.5 ∘C. Find the food caloric content of peanut butter.
Chemistry
1 answer:
devlian [24]4 years ago
8 0

Answer:

5927.3488 calorie/g

Explanation:

For peanut butter:

Mass = 15 g

Initial temperature = 22.4 °C

Final temperature = 25.5 °C

Specific heat of calorimeter, C = 120 kJ/°C

Considering

Q=C\times (T_f-T_i)

Q=120\ kJ/^0C\times (25.5-22.4)\ ^0C

Q=372\ kJ

Also,

1 kJ = 239.006 calories

So, Heat = 372*239.006 calories = 88910.232 calories

15 g of the peanut butter gives 88910.232 calories

<u>So, the food caloric content of peanut butter = 88910.232 calories/ 15 g = 5927.3488 calorie/g</u>

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Linolenic acid (C18H30O2 - M.W. = 278.42 g/mol) reacts with hydrogen gas according to the equation: C18H30O2 + 3H2 (g) → C18H36O
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Answer:

2.53 L is the volume of H₂ needed

Explanation:

The reaction is: C₁₈H₃₀O₂ + 3H₂ → C₁₈H₃₆O₂

By the way we can say, that 1 mol of linolenic acid reacts with 3 moles of oxygen in order to produce, 1 mol of stearic acid.

By stoichiometry, ratio is 1:3

Let's convert the mass of the linolenic acid to moles:

10.5 g . 1 mol / 278.42 g  = 0.0377 moles

We apply a rule of three:

1 mol of linolenic acid needs 3 moles of H₂ to react

Then, 0.0377 moles will react with (0.0377 . 3 )/1 = 0.113 moles of hydrogen

We apply the Ideal Gases Law to find out the volume (condition of measure are STP) → P . V = n . R . T → V = ( n . R .T ) / P

V = (0.113 mol . 0.082 L.atm/mol.K . 273.15K) 1 atm = 2.53 L

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3 years ago
Complete the sentence
solmaris [256]

Answer:

Explanation:

physical change

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3 years ago
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A 10 mm Brinell hardness indenter is used for some hardness testing measurements of a steel alloy. a) Compute the HB of this mat
Lady_Fox [76]

Explanation:

(a)  The given data is as follows.  

         Load applied (P) = 1000 kg

         Indentation produced (d) = 2.50 mm

         BHI diameter (D) = 10 mm

Expression for Brinell Hardness is as follows.

                HB = \frac{2P}{\pi D [D - \sqrt{(D^{2} - d^{2})}]}    

Now, putting the given values into the above formula as follows.

                HB = \frac{2P}{\pi D [D - \sqrt{(D^{2} - d^{2})}]}                            = \frac{2 \times 1000 kg}{3.14 \times 10 mm [D - \sqrt{((10 mm)^{2} - (2.50)^{2})}]}  

                       = \frac{2000}{9.98}                          

                       = 200

Therefore, the Brinell HArdness is 200.

(b)     The given data is as follows.

               Brinell Hardness = 300

                Load (P) = 500 kg

               BHI diameter (D) = 10 mm

             Indentation produced (d) = ?

                      d = \sqrt{(D^{2} - [D - \frac{2P}{HB} \pi D]^{2})}

                         = \sqrt{(10 mm)^{2} - [10 mm - \frac{2 \times 500 kg}{300 \times 3.14 \times 10 mm}]^{2}}

                          = 4.46 mm

Hence, the diameter of an indentation to yield a hardness of 300 HB when a 500-kg load is used is 4.46 mm.

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olya-2409 [2.1K]

Answer:

The equilibrium will shift to produce less ammonia

Explanation:

According to Le Chatelier's principle, the reaction will try to oppose anything that is done on it, if it was at equilibrium.

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