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-BARSIC- [3]
3 years ago
14

Which of these processes removes carbon from

Chemistry
1 answer:
GenaCL600 [577]3 years ago
3 0
Answer is c photosynthesis
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Which property controls the movement of groundwater by determining the rate at which water passes through the soil?
Dimas [21]

The answer is permeability

I took my test and it was right

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4 years ago
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Calculate the molarity of sodium ion in a solution made
Arada [10]

Answer:

0.1035 M

Explanation:

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Moles =Molarity \times {Volume\ of\ the\ solution}

Sodium chloride will furnish Sodium ions as:

NaCl\rightarrow Na^{+}+Cl^-

Given :

For Sodium chloride :

Molarity = 0.288 M

Volume = 3.58 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 3.58×10⁻³ L

Thus, moles of Sodium furnished by Sodium chloride is same the moles of Sodium chloride as shown below:

Moles =0.288 \times {3.58\times 10^{-3}}\ moles

Moles of sodium ions by sodium chloride = 0.00103104 moles

Sodium sulfate will furnish Sodium ions as:

Na_2SO_4\rightarrow 2Na^{+}+SO_4^{2-}

Given :

For Sodium sulfate :

Molarity = 0.001 M

Volume = 6.51 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 6.51 ×10⁻³ L

Thus, moles of Sodium furnished by Sodium sulfate is twice the moles of Sodium sulfate as shown below:

Moles =2\times 0.001 \times {6.51\times 10^{-3}}\ moles

Moles of sodium ions by Sodium sulfate = 0.00001302 moles

Total moles = 0.00103104 moles + 0.00001302 moles = 0.00104406 moles

Total volume = 3.58 ×10⁻³ L + 6.51 ×10⁻³ L = 10.09 ×10⁻³ L

Concentration of sodium ions is:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity_{Na^+}=\frac{0.00104406}{10.09\times 10^{-3}}

<u> The final concentration of sodium anion = 0.1035 M</u>

4 0
4 years ago
Sam is pushing a large rock over the ground. ALL BUT ONE of the following terms relates to the movement of the rock. What term i
zhannawk [14.2K]

Answer:

C) Mass

Explanation:

7 0
3 years ago
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A sample of gas has a mass of 0.673g. Its volume is 250.0mL at a temperature of 83 degrees C and a pressure of 747 torr. The sam
suter [353]

Answer:

Explanation:

Given data:

Mass of sample = 0.673 g

Volume = 250.0 mL (0.25 L)

Temperature = 83°C (273+83= 356 k)

Pressure = 747 torr (747/760 = 0.98 atm)

Gas type = ?

Solution:

PV = nRT

n = PV/RT

n = 0.98 atm× 0.25 L / 0.0821 atm. L/mol.K × 356 k

n = 0.245 / 29.23/mol

n = 0.01 mol

Number of moles = mass/ molar mass

Molar mass = 0.673 g /  0.01 mol

Molar mass = 67.3 g/mol

molar mass of  CO2 = 44 g/mol

molar mass of  H2 = 2.016 g/mol

molar mass of  SO3 = 80.066 g/mol

molar mass of  Ar = 40 g/mol

molar mass of  Xe = 131.3 g/mol

So non of these gases are present.

4 0
4 years ago
Which of the following correctly pairs a phase of
Harrizon [31]

Answer:

njhhhhhhh

Explanation:

8 0
3 years ago
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