All categories

3 years ago

3.Write the chemical equation for the reaction when methane burns in (2)

Chemistry

1 answer:

IceJOKER [234]3 years ago

5 0

Answer:

a)CH4 + O2 = CO2 + H2O

b)4CH4+5O=2CO+8H2O+2C

You might be interested in

How are elements that are gases at room temperature designated in the periodic table

Ira Lisetskai [31]

5= Elemental hydrogen, nitrogen, oxygen, fluorine and chlorine are all gases at room temperature,

4 0

3 years ago

What is the Kelvin temperature for 30°C?

Annette [7]

303.15 would be your answer

4 0

3 years ago

Na-23 has 12 neutrons. What is its atomic number

sweet-ann [11.9K]

Atomic number is 11.

4 0

3 years ago

The chemical equation below shows the decomposition of nitrogen triiodide (NI3) into nitrogen (N2) and iodine (I2). 2NI3 Right a

yuradex [85]

The moles of I₂ will form from the decomposition of 3.58g of NI₃ is 0.0136 moles.

<h3>How we calculate moles?</h3>

Moles of any substance will be calculated as:

n = W/M, where

W = required mass

M = molar mass

Given chemical reaction is:

2NI₃ → N₂ + 3I₂

Moles of 3.58g of NI₃ will be calculated as:

n = 3.58g / 394. 71 g/mol = 0.009 moles

From the stoichiometry of the solution, it is clear that:

2 moles of NI₃ = produce 3 moles of I₂

0.009 moles of NI₃ = produce 3/2×0.009=0.0136 moles of I₂

Hence, option (3) is correct i.e. 0.0136 moles.

To know more about moles, visit the below link:

brainly.com/question/15303663

8 0

2 years ago

Problem Page A chemist measures the amount of bromine liquid produced during an experiment. He finds that of bromine liquid is p

masha68 [24]

The question is incomplete, here is the complete question:

A chemist measures the amount of bromine liquid produced during an experiment. She finds that 766.g of bromine liquid is produced. Calculate the number of moles of bromine liquid produced. Round your answer to 3 significant digits.

<u>Answer:</u> The amount of liquid bromine produced is 4.79 moles.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

We are given:

Given mass of liquid bromine = 766. g

Molar mass of liquid bromine, $(Br_2)$ = 159.8 g/mol

Putting values in above equation, we get:

$\text{Moles of liquid bromine}=\frac{766.g}{159.8g/mol}=4.79mol$

Hence, the amount of liquid bromine produced is 4.79 moles.

6 0

3 years ago