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2 years ago

Why chlorine has high electroaffinity than flourine

Chemistry

1 answer:

Aleksandr-060686 [28]2 years ago

7 0

Answer:

Fluorine has seven electrons in 2p-subshell whereas chlorine has seven electrons in its 3p-subshell. 3p-subshell is relatively larger than 2p-subshell. Therefore, repulsion among the electrons will be more in the 2p-shell of fluorine than 3p-subshell in chlorine. Due to the smaller size and thus, the greater electron-electron repulsions, fluorine will not accept an incoming electron with the same as chlorine.

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HEY PLEASE THANK YOU

Goshia [24]

Radon hope this helps.

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3 years ago

Hello, can someone help me? Please<br> Which velocity changed the most?

saw5 [17]

Answer:

Explanation:

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3 years ago

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Answer:

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3 years ago

49.9 ml of a 0.00292 m stock solution of a certain dye is ddiluted to 1.00 L. the diluted solution has an absorbance of 0.600. w

inna [77]

Complete Question

49.9 ml of a 0.00292 m stock solution of a certain dye is diluted to 1.00 L. the diluted solution has an absorbance of 0.600. what is the molar absorptivity coefficient of the dye

Answer:

The value is $\epsilon = 4118.1 \ M^{-1} cm^{-1}$

Explanation:

From the question we are told that

The volume of the stock solution is $V_1 = 49.9 mL = 0.0499 \ L$

The concentration of the stock solution is $C_1 = 0.00292 \ M$

The volume of the diluted solution is $V_2 = 1.00 \ L$

The absorbance is $A = 0.600$

Generally the from the titration equation we have that

$C_1 * V_1 = C_2 * V_2$

=> $0.00292 * 0.0499 = C_2 * 1$

=> $C_2 = 0.0001457 \ M$

Generally from Beer's law we have that

$A = \epsilon * l * C_2$

=> $\epsilon = \frac{A}{ l * C_2 }$

Here l is the length who value is 1 cm because the unit of molar absorptivity coefficient of the dye is $M^{-1} * cm^{-1}$

$\epsilon = \frac{0.600}{ 1 * 0.0001457 }$

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3 years ago

The first step of electrophilic aromatic substitution involves the formation of the arenium ion intermediate.

Anastaziya [24]

Answer:

True

Explanation:

Aromatic compounds undergo substitution rather than addition reactions because the aromatic structure is maintained.

Electrophilic aromatic substitution begins with attack of the electrophile on the aromatic ring to yield a delocalized intermediate called the arenium intermediate. Loss of hydrogen from this intermediate yields the final product.

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4 years ago

Why chlorine has high electroaffinity than flourine​

Why chlorine has high electroaffinity than flourine