Answer:
-10/3 or -3.33
Step-by-step explanation:
substitute 0 for y
0 = 6x + 20
-20 = 6x + 20 - 20 subtract 20 on both sides
-20 = 6x divide by 6 on each side
-20/6 = 6x/6
x = -20/6 simplify
x = -10/3
Answer:
-8
Step-by-step explanation:
-8m⁴ n⁴
m = 0.5 = 1/2
n = 2
Substitute
-8 * (1/2)⁴ * (2)⁴
-8 * (1/16) * (16)
-8
The answer is 2x-y
step-by-step explanation
in order to simplify you have to come one like terms and in this case you have your 3x and you’re subtracting x which is also know as 1x.
3x - 1x = 2x (then you still have your y) so 2x-y
Vitvivuc vrivdfdxfdddxgtdcgyimbfdd
Answer:
- amount lent: ₹6000
- interest received: Kamal, ₹600; Anand, ₹615.
Step-by-step explanation:
For principal P invested at simple interest rate r, the returned value in t years is ...
A = P(1 +rt)
If K is Kamal's returned value, the given numbers tell us ...
K = P(1 +0.05·2) = 1.1P
__
For principal P invested at compound interest rate r, with interest compounded annually for t years, the returned value is ...
A = P(1 +r)^t
If A is Anand's returned value, the given numbers tell us ...
A = P(1.05)² = 1.1025P
This latter amount is RS.15 more than the former one, so we have ...
1.1025P = 1.1P +15
0.0025P = 15 . . . . . . . . subtract 1.1P
P = 6000 . . . . . . . . . . . divide by 0.0025 . . . . the amount lent
Kamal received 1.1P -P = 0.1P = 600 on the investment.
Each lent ₹6000. Kamal received ₹600 in interest; Anand received ₹615 in interest.
