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Aleksandr-060686 [28]
3 years ago
8

if the displacement of a car was 150 km [E] and the velocity was 15.0 km/h [E], what was the travel time?

Physics
1 answer:
soldi70 [24.7K]3 years ago
4 0
Given,
Displacement of the car = 150 km
Velocity of the car = 15.0 km/h

We need to calculate the travel time t

We all know that the formula to calculate velocity is

Velocity = displacement / time

From the above equation,

Time = Displacement / Velocity

Substituting the values in the above equation, 

Time = 150 / 15.0 = 10 hours
Therefore, travel time = 10 hours.
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A grapefruit falls from a tree and hits the ground .75 seconds later. How far did the grapefruit drop? What was its speed?
Ivanshal [37]
1) The grapefruit is in free fall, so it moves by uniformly accelerated motion, with constant acceleration g=9.81 m/s^2. Calling h its height at t=0, the height at time t is given by
h(t)=h- \frac{1}{2}gt^2
We are told thatn when t=0.75 s the grapefruit hits the ground, so h(0.75 s)=0. If we substitute these data into the equation, we can find the initial height h of the grapefruit:
0=h- \frac{1}{2}gt^2
h= \frac{1}{2}gt^2= \frac{1}{2}(9.81 m/s^2)(0.75 s)^2=2.76 m

2) The speed of the grapefruit at time t is given by
v(t)=v_0 +gt
where v_0=0 is the initial speed of the grapefruit. Substituting t=0.75 s, we find the speed when the grapefruit hits the ground:
v(0.75 s)=gt=(9.81 m/s^2)(0.75 s)=7.36 m/s
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A light-year is a measurement of _____.<br> a. time<br> b. gravity<br> c. energy<br> d. distance
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D. distance

A light-year is the distance light would travel in 1 year.
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The charge not experience a net magnetic force if it moves to the right.

<h3>What is the magnetic force?</h3>

The magnetic force is a force that is felt by an object owing to the presence of a magnet. We should note that when a charge is placed in a magnetic field, it experiences a magnetic force.

The direction in which the charge will experience no net magnetic force is when the charge moves towards the right.

Learn more about magnetic field:brainly.com/question/3673512

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Explanation:

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A resistor of 5 Ω is placed in a circuit. The voltage drop across the resistor is 12 V. What is the current through the resistor
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<span>Data:

</span>R = 5 Ω
U = 12 V
i = ?
<span>
Formula:

</span>U = R*i → i =  \frac{U}{R}<span>

Solving:

</span>i = \frac{U}{R}
i = \frac{12}{5}
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Answer:

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