What is the average speed of the marble as it rolls across the floor?

A proton with kinetic energy of 1.16×105 eV is fired perpendicular to the face of a large plate that has a uniform charge densit

Nezavi [6.7K]

Answer:

force on the proton = 5.96 × $10^{-14}$ N

Explanation:

given data

kinetic energy = 1.16 × $10^{5}$ eV

charge density of σ = +6.60 μC/m²

solution

we get here force on the proton that is express as

F = qE ....................1

here q is charge on proton i.e = 1.6 × $10^{-19}$ C

and E is electric field due to charge i.e E = $\frac{\sigma }{2*\epsilon_o }$

so put the value in equation 1 we get

force on the proton = 1.6 × $10^{-19}$ × $\frac{6.60*10^{-6}}{2*8.85*10^{-12}}$

force on the proton = 5.96 × $10^{-14}$ N

7 0

3 years ago

A single conducting loop of wire has an area of 7.26E-2 m2 and a resistance of 117 Ω. Perpendicular to the plane of the loop is

cricket20 [7]

Answer:

$\frac{dB}{dt}$ = 591.45 T/s

Explanation:

i = induced current in the loop = 0.367 A

R = Resistance of the loop = 117 Ω

E = Induced voltage

Induced voltage is given as

E = i R

E = (0.367) (117)

E = 42.939 volts

$\frac{dB}{dt}$ = rate of change of magnetic field

A = area of loop = 7.26 x 10⁻² m²

Induced emf is given as

$E = A\frac{dB}{dt}$

$42.939 = (7.26\times 10^{-2})\frac{dB}{dt}$

$\frac{dB}{dt}$ = 591.45 T/s

3 0

3 years ago

Which has more calories Donuts or Apples?

anyanavicka [17]

Donut

$\: \: \: \:$

3 0

3 years ago

An electron in a hydrogen atom jumps from the n = 3 state to the ground state. Which of the following statements can you deduce

anyanavicka [17]

Answer:

B) True. It is the photon is emitted the wavelength is correct

Explanation:

For this exercise let's use the Bohr model for the hydrogen atom

Eₙ = -13.606 / n2

This gives the energy of the levels in eV. let's look for the energy

n = 1

E₁ = -13,606

n = 3

E₃ = -13.606 / 3²

E₃ = -1.512 eV

The transition occurs when moving from one level to another

ΔE = E₃ -E₁

ΔE = -1.512 + 13.606

ΔE = 12.094 eV

Now let's use the Planck equation and the speed of light for the energy of the transition

E = h F

c = λ f

E = h c / λ

E = 6.63 10⁻³⁴ 3 10⁸ / λ

E = 19.89 10⁻²⁶ /λ

λ = 19.89 10⁻²⁶ / E

Let's reduce energy to July

E = 12,094 eV (1.6 10⁻¹⁹ J / 1 eV) = 19.35 10⁻¹⁹ J

λ = 19.89 10⁻²⁶ / 19.35 10⁻¹⁹

λ = 1.0279 10⁻⁷ m

Let's reduce to nm

λ = 1.0279 10⁻⁷ m (10⁹ nm / 1 m)

λ = 102.79 nm

Let's examine the answers

A) False is another wavelength and the photon emitted

B) True. It is the photon is emitted the wavelength is correct

C) False. Wavelength is different

D) False the photon is emitted

E) False wavelength is different

7 0

4 years ago

A car weighing 9800 N travels at 30 m/s. What braking force brings it to rest in 100m? In 10 m?

Svetach [21]

As per kinematics equation we know that

final speed of the car = 0 m/s

initial speed is given as 30 m/s

distance moved = 100 m

now we have

$v_f^2 - v_i^2 = 2 a d$

$0 - 30^2 = 2(a)(100)$

$a = - 4.5 m/s^2$

now braking force is given as

$F = ma$

now for mass we know that the weight of car is

$W = mg = 9800 N$

so mass of car is

$m = 1000 kg$

now we have

$F = 1000(4.5) = 4500 N$

Part b)

Again we have

final speed of the car = 0 m/s

initial speed is given as 30 m/s

distance moved = 10 m

now we have

$v_f^2 - v_i^2 = 2 a d$

$0 - 30^2 = 2(a)(10)$

$a = - 45 m/s^2$

now braking force is given as

$F = ma$

mass of car is

$m = 1000 kg$

now we have

$F = 1000(45) = 45000 N$

4 0

3 years ago