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diamong [38]
3 years ago
6

An area of the sky where multiple meteors can be sometimes observed is referred to as a:

Physics
1 answer:
vodka [1.7K]3 years ago
7 0

it would be a meteor shower

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The strength of a magnetic field is an indication of how many flux lines per square inch there are. This is called
Nat2105 [25]

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gauss

Explanation:

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3 years ago
You nose out another runner to win the 100.000m dash. If your total time for the race was 11.8 seconds and you aced out the othe
daser333 [38]
You completed 100.000 m in 11.800 second

you aced out the other runner by 0.001 seconds

time taken by other runner to finish = 11.800 + 0.001 = 11.801s

speed of other runner = 100/11.801 m/s

distance covered by him in 11.8 s = 100/11.801 × 11.8 = 99.992 m

you won by = 100 - 99.992 = 0.008 meter
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4 years ago
Describe how the student should measure the time taken for the toy parachute to
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t = √(2d/g)

4 0
3 years ago
If you are an astronaut in the middle of the near side of the moon during a full moon,how would the ground around you look?How w
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The moon would be bright and the earth would be darker because the sun is on the opposite side of the earth at that time and the light from it is reflecting off the moon to produce light upon the nigh also.......

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3 years ago
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The man is walking with speed v1 = 1.35 m/s to the right when he trips over a small floor discontinuity. Estimate his angular ve
soldier1979 [14.2K]

Answer:

The angular velocity, \omega = 1.05 rad/s clockwise

Explanation:

The mass of the man, m = 72 kg

The center of mass of the man will be at the middle of his body, particularly around his abdomen.

Height of the center of mass, h = 0.71 m

The speed of the man, v₁ = 1.35 m/s

Moment of inertia about the ankle joint, I = 66 kg/m²

Based on the principle of conservation of angular momentum (about the ankle joint):

Angular momentum before impact = Angular momentum after impact

Angular momentum before impact = -mv₁h

Angular momentum before impact = -(72 * 1.35 * 0.71)

Angular momentum before impact = -69.012 kg m²/s...............(1)

Angular momentum after impact = I \omega

Angular momentum after impact = 66 * \omega.................(2)

66 \omega = -69.012\\\omega = -69.012/66\\\omega = -1.05 rad/s

The angular velocity, \omega = 1.05 rad/s clockwise

8 0
3 years ago
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