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just olya [345]
3 years ago
6

An electric heater is operated by applying a potential difference of 78.0 V across a nichrome wire of total resistance 7.00 Ω. a

) Find the current in the wire. Answer in units of A.
b) Find the power rating of the heater. Answer in units of W.
Physics
1 answer:
aleksley [76]3 years ago
8 0

PART A)

Here we know that

potential difference across the wire is

V = 78 volts

resistance of wire is

R = 7 ohm

now by ohm's law

V = iR

78 = i(7 ohm)

i = 11.14 A

Part b)

Power rating is defined as rate of electrical energy

it is defined as

P = iV

now we have

P = 11.14 ( 78)

P = 869.1 Watt

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Answer:

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Explanation:

From the question we are told that

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   The amplitude of the  oscillation t the beginning is x =  6.70 cm = 0.067 \  m

    The amplitude after time t is  x_t = 2.20 cm = 0.022 \  m

    The number of oscillation is N  = 30

Generally the time taken to attain the second amplitude is mathematically represented as

       t  = N  *  T                                            Here  T is the period of oscillation

         t = N * 2\pi \sqrt{\frac{m}{k} }

=>     t = 30 * 2 * 3.142 *  \sqrt{\frac{ 0.490}{11.5} }

=>     t = 38.88 \  s

Generally the amplitude at time t is mathematically represented as

         x(t) = x e^{-\frac{at}{2m} }

Here a is the damping  constant so

 at  t = 38.88 \  s ,  x_t = 2.20 cm = 0.022 \  m

So  

     0.022 = 0.067 e^{-\frac{a * 38.88}{2 * 0.490} }

=>  0.3284 = e^{-\frac{a * 38.88}{2 * 0.490} }

taking natural log of both sides

=>  ln(0.3284 ) = -\frac{a * 38.88}{2 * 0.490} }    

=>   a = 0.028

Generally the time constant is mathematically represented as

    \tau = \frac{m}{a}      

=> \tau = \frac{0.490}{  0.028}    

=> \tau = 17.5 \ s    

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