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Ira Lisetskai [31]
3 years ago
13

A 5 kg object near Earth's surface is released from rest such that it falls a distance of 10 m. After the object falls 10 m, it

has a speed of 12 m/s. Which of the following correctly identifies whether the object-Earth system is open or closed and describes the net external force?
A) The system is closed, and the net external force is zero.
B) The system is open, and the net external force is zero.
C) The system is closed, and the net external force is nonzero.
D)The system is open, and the net external force is nonzero.
Physics
1 answer:
galben [10]3 years ago
4 0

To solve the problem it is necessary to apply the concepts related to energy conservation. We have a mass of 5Kg that at a distance of 10m has gained 12m / s, with energy losses due to friction.

KE + W_f = PE

\frac{1}{2}mv^2 +W_f = mgh

W_f = \frac{1}{2}mv^2 -mgh

W_f = \frac{1}{2} 5*12^2-5*9.8*10

W_f = 130J

Since there is a loss of energy due to friction, it means that an external force resulting from friction is interacting on the system, which also makes the system open.

The correct answer is D.

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Answer:

F = 0.78[N]

Explanation:

The given values correspond to forces, we must remember or take into account that the forces are vector quantities, that is, they have magnitude and direction. Since we have two X-Y coordinate axes (two-dimensional), we are going to decompose each of the forces into the X & y components.

<u>For F₁</u>

<u />F_{y}=2[N]<u />

<u>For F₂</u>

F_{x}=2*cos(60)\\F_{x}=1[N]\\F_{y}=-2*sin(60)\\F_{y}=-1.73[N]

<u>For F₃</u>

<u />F_{x}=-1*sin(60)\\F_{x}=-0.866[N]\\F_{y}=1*cos(60)\\F_{y}=0.5 [N]<u />

Now we can sum each one of the forces in the given axes:

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Now using the Pythagorean theorem we can find the total force.

F=\sqrt{(0.134)^{2} +(0.77)^{2}}\\F= 0.78[N]

8 0
3 years ago
A boy pushes a cart with a constant velocity of 0.5m/s by applying a force of 60 N. What is the total frictional force acting on
Nutka1998 [239]

Answer:

60N

Explanation:

in this case the minimum amount of force required must be equal to the friction Force. i.e <u>Newton</u><u>'s</u><u> </u><u>first</u><u> </u><u>law</u><u> of</u><u> </u><u>mot</u><u>ion</u><u>.</u>

therefore the maximum amount of frictional force is equal to the applied force which is 60N.

because of the net force acting on the object is zero the object is in constant motion . i.e equal and opposite force must be applied so that the object is in constant velocity therefore the total frictional force must be 60N

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The sum of the initial speeds must be equal to the sum of the final ones.

If we are told that kinetic energy must be conserved also, simplifying, we can write:

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The only condition that satisfies  (1) and (2) simultaneously is the one in which both masses exchange speeds, so we can write:

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Answer: C and D

Explanation: a p e x

4 0
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