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garik1379 [7]
3 years ago
6

Compare landslides and slumps.

Physics
2 answers:
Oduvanchick [21]3 years ago
7 0
One is more deadly than the other
Yuki888 [10]3 years ago
4 0

Answer:

Landslides are natural disasters and slumps are heavy or helpless collapses. Landslides are deadly where slumps aren't

Explanation:

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Nicholas spends 20 minutes ironing shirts with his 1,800-watt iron. How many joules of energy were used
ivanzaharov [21]
Multiply the power (1,800 watts) by time (1,200 seconds) to get 2,160,000 joules (or 2.16 MJ)
7 0
3 years ago
The conductors that carry the current to electrical devices and ? equipment are the heart of all electrical systems. There are a
Aleksandr [31]

Answer:

Utilization, effects

Explanation:

The conductors that carry the current to electrical devices and utilization equipment are the heart of all electrical systems. There are associated effects whenever current flows through a conductor.

7 0
4 years ago
How many days does the average male live?
Marysya12 [62]
Answer:

An average male lives 27,375 Days
4 0
4 years ago
In the first stage of a two-stage Carnot engine, energy is absorbed as heat Q1 at temperature T1 = 500 K, work W1 is done, and e
Nataly [62]

Answer:

Efficiency = 52%

Explanation:

Given:

First stage

heat absorbed, Q₁ at temperature T₁ = 500 K

Heat released, Q₂ at temperature T₂ = 430 K

and the work done is W₁

Second stage

Heat released, Q₂ at temperature T₂ = 430 K

Heat released, Q₃ at temperature T₃ = 240 K

and the work done is W₂

Total work done, W = W₁ + W₂

Now,

The efficiency is given as:

\eta=\frac{\textup{Total\ work\ done}}{\textup{Energy\ provided}}

or

Work done = change in heat

thus,

W₁ = Q₁ - Q₂

W₂ = Q₂ - Q₃

Thus,

\eta=\frac{(Q_1-Q_2)\ +\ (Q_2-Q_3)}{Q_1}}

or

\eta=1-\frac{(Q_1-Q_3)}{Q_1}}

or

\eta=1-\frac{(Q_3)}{Q_1}}

also,

\frac{Q_1}{T_1}=\frac{Q_2}{T_2}=\frac{Q_3}{T_3}

or

\frac{T_3}{T_1}=\frac{Q_3}{Q_1}

thus,

\eta=1-\frac{(T_3)}{T_1}}

thus,

\eta=1-\frac{(240\ K)}{500\ K}}

or

\eta=0.52

or

Efficiency = 52%

8 0
4 years ago
A horizontal clothesline is tied between 2 poles, 12 meters apart. When a mass of 1 kilograms is tied to the middle of the cloth
nadya68 [22]

Answer:

The  tension on the clotheslines is  T  = 8.83 \ N

Explanation:

The  diagram illustrating this  question is  shown on the first uploaded image

From the question we are told that  

    The distance between the two poles is  d =  12 \ m

     The mass tie to the middle of the clotheslines m  =  1 \ kg

     The length at which the clotheslines sags is  l  = 4 \ m

Generally the weight due to gravity at the middle of the  clotheslines is mathematically represented as

          W =  mg

let the angle which the tension on the  clotheslines makes with the horizontal be  \theta which mathematically evaluated using the SOHCAHTOA as follows

        Tan  \theta =  \frac{ 4}{6}

=>     \theta =  tan^{-1}[\frac{4}{6} ]

=>     \theta  =  33.70^o

   So the vertical component of this  tension is  mathematically represented a  

      T_y  = 2*  Tsin \theta

Now at equilibrium the  net horizontal force is  zero which implies that

          T_y  -  mg  = 0

=>       T sin \theta  -  mg  =  0

substituting values

          T  =   \frac{m*g}{sin (\theta )}

substituting values

           T  =   \frac{1 *9.8}{2 * sin (33.70 )}

           T  = 8.83 \ N

6 0
3 years ago
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