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pantera1 [17]
3 years ago
12

What information on the periodic table is used to complete electron dot diagrams? The number before the A at the top of a column

shows how many dots to draw in the diagram. The number before the B at the top of a column shows how many dots to draw in the diagram. The number at the left of each row shows the number of valence electrons that are in atoms of elements in that row. The number at the left of each row shows how many dots to draw above the symbol for elements in that row.
Chemistry
2 answers:
zmey [24]3 years ago
8 0
The answer is <span>The number before the A at the top of a column shows how many dots to draw in the diagram.</span>
Ann [662]3 years ago
8 0
<h3><u>Answer;</u></h3>

The number before the A at the top of a column shows how many dots to draw in the diagram.

<h3><u>Explanation</u>;</h3>
  • Electron dot structures are structures in which electrons are represented by dots placed around a chemical symbol. Therefore, in a dot diagram only the symbol for the element and the electrons in its outermost energy level are shown.
  • The reason as to why valence electrons are the only ones used in dot diagram is because; they are the only ones involved in chemical reactions and bonding, to make it easier to decide what it could be bonded to and its characteristics. Also to make it easier identify its placement on periodic table.
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The density of solid Cr is 7.15 g/cm3. How many atoms are present per cubic centimeter of Cr?
Masja [62]
To calculate the number of atoms of Cr, we first find the number of moles per unit of cubic centimeter of Cr. Then, use avogadros number for the number of atoms. Calculations are as follows:

1 cm^3 (7.15 g/cm^3) (1 mol / 51.996 g Cr) = 0.14 mol Cr

0.14 mol Cr ( 6.022 x 10^23 atoms Cr / 1 mol Cr ) = 8.28 x 10^22 atoms Cr
8 0
4 years ago
Why can we only see water vapor right above the boiling water
FinnZ [79.3K]

Answer:

Explanation:

Because of heat

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4 years ago
This system is at equilibrium, what change would shift the equilibrium to the right?
Sidana [21]

Answer:

fjrhg

Explanation:

8 0
3 years ago
If you were to use Lewis theory to predict the formula for the compound between rubidium and fluorine, it would most likely be:
goldenfox [79]

<u>Answer:</u> The formula of the compound formed between rubidium and fluorine is RbF

<u>Explanation:</u>

Ionic bond is defined as the bond which is formed by complete transfer of electrons from one atom to another atom.

The atom which looses the electron is known as electropositive atom and the atom which gains the electron is known as electronegative atom. This bond is usually formed between a metal and a non-metal.

Rubidium is the 37th element of the periodic table having electronic configuration of 1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^1

This will loose 1 electron to form Rb^+ ion

Fluoride is the 9th element of the periodic table having electronic configuration of 1s^22s^22p^5

This will gain 1 electron to form F^- ion

To form RbF compound, 1 rubidium ion is needed to neutralize the charge on fluoride ion

The formation of the given compounds is shown in the image below.

4 0
3 years ago
Air in a 0.3 m3 cylinder is initially at a pressure of 10 bar and a temperature of 330K. The cylinder is to be emptied by openin
sergiy2304 [10]

Answer:

(a) Temperature = 330 K, and mass = 0.321 kg

(b) T₂ = 171.56 K, mass = 0.32223 kg

Explanation:

For a constant temperature process we have

p₁v₁ = p₂v₂

Where p₁ = initial pressure = 10 bar = 1000000 Pa

p₂ = final pressure = 1 atm = 101325 Pa

v₁ initial volume = 0.3 m³

v₂ = final volume = unknown

From the relation we have v₂ = 2.96 m³

Therefore at constant temperature 2.93 m³ - 0.3 m³ or 2.66 m³ will be expelled from the container

Temperature = 330 K, and mass =

Also from the relation p1v1 = mRT1

We have, (1000000×0.3)/(8314×330) = 109..337 mole

For air mass

Mass = 3.171 kg

After opening we have

p2v2/(RT1) = n2 = 11.07 mol or 0.321 kg

or

(b) This is said to be adiabatic condition hence

Here

But cp = 29 (J/mol K).

and p₁v₁ = RT₁ therefore R = 1000000*0.3/330 = 909.1 J/mol·K

And For perfect gas γ = 1.4

Hence T₂ = 171.56 K

γ =cp/cv therefore cv=cp/γ = 29/1.4 = 20.714 (J/mol K). and R =cp-cv = 8.29 J/mol·K

Therefore p1v1/(RT1) = 109.66 moles and we have

p2v2/(R×T2) = 11.11 mole left

For air that is 0.32223 kg

5 0
4 years ago
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