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nasty-shy [4]
3 years ago
8

The heating curve for a sample of pure ethanol shows the slope of the line for gaseous state is greater than the slope of the li

ne for the liquid state.
Which statement below explains that?a. The specific heat capacity of the gaseous ethanol is less than the specific heat capacity of liquid ethanol.b. The specific heat capacity of the gaseous ethanol is greater than the specific heat capacity of liquid ethanol.c. The heat of vaporization of ethanol is less than the heat of fusion of ethanol.d. The heat of vaporization of ethanol is greater than the heat of fusion of ethanol.
Chemistry
1 answer:
Agata [3.3K]3 years ago
3 0

Answer:

a. The specific heat capacity of the gaseous ethanol is less than the specific heat capacity of liquid ethanol.

Explanation:

The heating curve is a curve that represents temperature (T) in the y-axis vs. added heat (Q) in the x-axis. The slope is T/Q = 1/C, where C is the heat capacity. Then, the higher the slope, the lower the heat capacity. For a constant mass, it can also represent the specific heat capacity (c).

Heats of vaporization and fusion cannot be calculated from these sections of the heating curve.

<em>Which statement below explains that?</em>

<em>a. The specific heat capacity of the gaseous ethanol is less than the specific heat capacity of liquid ethanol.</em> YES.

<em>b. The specific heat capacity of the gaseous ethanol is greater than the specific heat capacity of liquid ethanol.</em> NO.

<em>c. The heat of vaporization of ethanol is less than the heat of fusion of ethanol.</em> NO.

<em>d. The heat of vaporization of ethanol is greater than the heat of fusion of ethanol.</em> NO.

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<h3>What is Empirical Formula ?</h3>

Empirical formula is the simplest whole number ratio of atoms present in given compound.

Element   %   Atomic mass   Relative no. of atoms  Simplest whole ratio

C            83.87       12                     \frac{83.87}{12} = 6.98                   \frac{6.98}{0.25} = 3

H            11.99         1                       \frac{11.99}{1} = 11.09                  \frac{11.09}{0.25} = 4

O            4.14          16                      \frac{4.14}{16} = 0.25                    \frac{0.25}{0.25} = 1

Thus the empirical formula is C₃H₄O₁.

<h3>How to find the Molecular formula of compound ?</h3>

Molecular formula = Empirical formula × n

n = \frac{\text{Molecular weight}}{\text{Empirical formula weight}}

  = \frac{386.64}{56}

  = 7

Molecular formula = Empirical formula × n

                               = 7 (C₃H₄O₁)

Thus from the above conclusion we can say that The main constituent of gallstones is cholesterol. Cholesterol may have a role in heart attacks and blood clot formation. Its elemental percentage composition is 83.87% C, 11.99% H, and 4.14% O. It has a molecular weight of 386.64 amu. Empirical formula is C₃H₄O₁ and Molecular formula is 7(C₃H₄O₁).

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