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alexandr1967 [171]
2 years ago
10

(((NEED ANSWER QUICK!!!))) Which is the stronger conjugate base, CN- or OCN-? Explain

Chemistry
1 answer:
Shkiper50 [21]2 years ago
6 0

Answer:

The stronger conjugate base will be the weaker acid; i.e., the acid with the smaller Ka-value.

Explanation:

Given conjugate base CN⁻ => weak acid => HCN =>  Ka =4.9 x 10⁻¹⁰

Given conjugate base OCN⁻ => weak acid=> HOCN => Ka = 3.5 x 10⁻⁴

Ka(HCN) << Ka(HOCN) => CN⁻ is a much stronger conjugate base than OCN⁻

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Answer:

B. That energy can only be converted between different forms

Explanation:

The law of conservation of energy implies that energy can only be converted between different forms but can neither be created nor destroyed.

Energy is the ability to do work. It is very important physical quantity that is essential to all life forms.

Energy according to the law of conservation of energy is not produced neither is it destroyed.

Energy is simply transformed from one form to another.

4 0
2 years ago
In this reaction: Mg (s) + I₂ (s) → MgI₂ (s), if 10.0 g of Mg reacts with 60.0 g of I₂, and 53.88 g of MgI₂ form, what is the pe
ad-work [718]

We know the law of conservation of mass

  • It states that mass is neither formed nor destroyed in any chemical reaction.
  • Mass of reactants=Mass of products.

Here

  • Mg and I_2 are reactants
  • MgI_2 is product with some yield.
  • Mass of reactants=10+60.0=70.0g
  • Mass of MgI_2=53.88g
  • Mass of yield=Product-MgI_2=70-53.88=16.12g

Lets find the percentage

\\ \tt\hookrightarrow \dfrac{Mass\:of\:yield}{Total\:mass}\times 100

\\ \tt\hookrightarrow \dfrac{16.12}{70}\times 100

\\ \tt\hookrightarrow 0.23028(010)=23.028\%

6 0
2 years ago
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What is a base used in toothpaste
lakkis [162]

The base of toothpaste is magnesium hydroxide.


8 0
3 years ago
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How many moles of hydrogen atoms are in 1 mole of sulfuric acid?
Andrews [41]

Answer:

2 moles

Explanation:

In one mole of sulfuric acid

There is 2 moles of hydrogen

4 moles of oxygen

and 1 mole of sulfur.

7 0
2 years ago
The first ionization energy, e, of a potassium atom is 0.696 aj. what is the wavelength of light, in nm, that is just sufficient
elena55 [62]
The formula to be used for this problem is as follows:

E = hc/λ, where h is the Planck's constant, c is the speed of light and λ is the wavelength. Also 1 aJ = 10⁻¹⁸ J

0.696×10⁻¹⁸ = (6.62607004×10⁻³⁴ m²·kg/s)(3×10⁸ m/s)/λ
Solving for λ,
λ = 2.656×10⁻⁷ m or <em>0.022656 nm</em>
6 0
2 years ago
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