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3 years ago

What is the mass, in grams, of a liquid having a density of 1.50g/mL and a volume of 3500mL

Chemistry

1 answer:

mojhsa [17]3 years ago

5 0

Answer:

5,250g

Explanation:

Density = Mass / Volume

*Note: mass = x

1.50g/mL = x / 3500mL

multiply 3500mL on both sides

1.50g/mL * 3500mL = 3500mL(x) / 3500mL

cancel units

x = 5250g

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Calculate the mass of H2OH2O produced by metabolism of 1.6 kgkg of fat, assuming the fat consists entirely of tristearin (C57H11

kakasveta [241]

Answer: 1779.8g of H2O

Explanation:

C57H110O6 + O2 —> CO2 + H20

To calculate the amount of water(H2O) produced by the reaction of 1.6Kg tristearin(C57H110O6) and O2, we must first balance the equation.

To do so, add 2 in front of C57H110O6, 163 in front of O2, 114 in front of CO2 and 110 in front of H2O i.e

2C57H110O6 + 163O2 —> 114CO2 + 110H20

Next, we have to calculate the mass of tristearin(C57H110O6) that reacted and the mass of water produced from the balanced equation. This can be done by:

MM of C57H110O6 = (57x12) + (110x1) + (6x16) = 684 + 110 + 96 = 890g/mol

Mass conc of C57H110O6 = 890 x 2 = 1780g

MM of H2O = (2x1) + 16 = 18g/mol

Mass conc of H2O = 110 x 18 = 1980g

Next, we will find the amount of water produced by 1.6Kg(i.e 1600g) of tristearin(C57H110O6). This is done by:

From the equation,

1780g of C57H110O6 produced 1980g of H2O.

Therefore 1600g of C57H110O6 will produce = (1600x1980)/1780 = 1779.8g of H2O

5 0

3 years ago

How many grams of C8H18<br> is in 405,576.398 mL

nevsk [136]

$Molarity X \frac{0.762 mol}{05.576398 L} = Mass$ is the of $C_8H_1_8$ is in 405,576.398 mL.

<h3>What is molarity?</h3>

Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution. Molarity is also known as the molar concentration of a solution.

Given data:

Molar mass of $C_8H_1_8$ = 0.762 mol

Volume of solution = 405,576.398 mL = 405,576.398 mL/1000 = 405.576398 L

Solution:

Step 1: Calculating moles of $C_8H_1_8$

• Molarity = $\frac{\;Moles \;of \;solute}{\;Volume \;of \;solution \;in \;litre}$

• Putting the value in the given formula

• Moles of solute C8H18 = $\frac{\;Mass}{\;Molar \;molar \;mass}$

• Moles of solute C8H18 = $\frac{\;Mass}{0.762 mol}$

Now,

Molarity = $\frac{\;Moles \;of \;solute}{\;Volume \;of \;solution \;in \;litre}$

Molarity = $\frac{\frac{\;Mass}{0.762 mol}}{\;Volume \;of \;solution \;in \;litre}$

Molarity = $\frac{\frac{\;Mass}{0.762 mol}}{405.576398 L}$

$Molarity X \frac{0.762 mol}{05.576398 L} = Mass$

Hence, $Molarity X \frac{0.762 mol}{05.576398 L} = Mass$ is the of $C_8H_1_8$ is in 405,576.398 mL.

Learn more about molarity here:

brainly.com/question/2817451

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Answer:

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