26.4 kg of calcium hydroxide (Ca(OH)₂)
Explanation:
We have the following chemical reaction:
CaO + H₂O → Ca(OH)₂
molecular weight of Ca(OH)₂ = atomic mass of Ca × number of Ca atoms + atomic mass of O × number of O atoms + atomic mass of H × number of H atoms
molecular weight of Ca(OH)₂ = 40 × 1 + 16 × 2 + 1 × 2 = 74 g/mole
molecular weight of CaO = atomic mass of Ca × number of Ca atoms + atomic mass of O × number of O atoms
molecular weight of CaO = 40 + 16 = 56 g/mole
number of moles = mass / molecular weight
number of moles of CaO = 20 / 56 = 0.357 kmoles
Taking in account the chemical reaction we devise the following reasoning:
if 1 kmole of CaO produces 1 kmole of Ca(OH)₂
then 0.357 kmoles of CaO produces X kmoles of Ca(OH)₂
X = (0.357 × 1) / 1 = 0.357 kmoles of Ca(OH)₂
mass = number of moles × molecular weight
mass of Ca(OH)₂ = 0.357 × 74 = 26.4 kg
Learn more about:
number of moles
brainly.com/question/10165629
brainly.com/question/9081560
#learnwithBrainly
Answer:
How many grams of H2 can be produced from the reaction of 11.5 grams of sodium with an excess of water? Hint: 2Na + 2H2O ---> 2NaOH + H2. Ans: 0.505g .
Explanation:
Answer:
The net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide is -470.4 kJ/mol.
Explanation:
Step 1 : Calcium carbide and water react to form acetylene and calcium hydroxide
..[1]
Step 2 : Acetylene, carbon dioxide and water react to form acrylic acid
..[2]
Using Hess's law:
[1] × 6 + [2]
The energy released on formation of 5 moles of acrylic acid = -2352 kJ
The energy released on formation of 1 moles of acrylic acid :
Hence, the net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide is -470.4 kJ/mol.
2.5 i believe i'll keep you updated i'm still trying to check my answers
Answer:
1 mole of Al2O3 = 102 grams
1 mole of Al2 = 54 grams
102 grams of Al2O3 contains = 54 gram of Al2
10kg of Al2O3 contains = (54/102)*10000g Al2
= 5294.11 g Al2 or 5.29411 kg
