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Goshia [24]
4 years ago
12

Can you help me out with the answer

Mathematics
1 answer:
Y_Kistochka [10]4 years ago
6 0

Answer:

B) 13.3

Step-by-step explanation:

10×8÷6=13.3

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Es aquella línea que no tiene partes rectas<br>​
Andru [333]

Answer:

is that line that does not have straight parts

Step-by-step explanation:

7 0
3 years ago
Which expression is equivalent to 72ab + 56a? <br> List All Possible Equivalents
krok68 [10]

Answer:

Step-by-step explanation:

Find equivalent fractions. Enter a fraction, mixed number or integer to get fractions that are equivalent to your input. Example entries:

Fraction - like 2/3 or 15/16

Mixed number - like 1 1/2 or 4 5/6

Integer - like 5 or 28

5 0
3 years ago
Someone please help me
Mashcka [7]
To solve this, we would need to know some trigonometry. 
To solve this, the equation would be this:
tan 37= x/3.
If we solve this, line segment DE would be approximately 2.26.
Hope this helps.
4 0
3 years ago
Consider the function g(x) = (x-e)^3e^-(x-e). Find all critical points and points of inflection (x, g(x)) of the function g.
Elden [556K]

Answer:

The answer is "cirtical\  points \ (x,g(x))\equiv  (e,0),(e+3,\frac{27}{e^3})"

Step-by-step explanation:

Given:

g(x) = (x-e)^3e^{-(x-e)}

Find critical points:

g(x) = (x-e)^3e^{(e-x)}

differentiate the value with respect of x:

\to g'(x)= (x-e)^3 \frac{d}{dx}e^{e-r} +e^{e-r}  \frac{d}{dx}(x-e)^3=(x-e)^2 e^{(e-x)} [-x+e+3]

critical points g'(x)=0

\to (x-e)^2 e^{(e-x)} [e+3-x]=0\\\\\to e^{(e-x)}\neq 0 \\\\\to (x-e)^2=0\\\\ \to [e+3-x]=0\\\\\to x=e\\\\\to x=e+3\\\\\to x= e,e+3

So,

The critical points of (x,g(x))\equiv  (e,0),(e+3,\frac{27}{e^3})

7 0
3 years ago
A jury pool consists of 27 people, 14 men and 13 women. Compute the probability that a randomly selected jury of 12 people is al
zlopas [31]

Answer:   \dfrac{7}{1,337,220}=5.2\times 10^{-6}

<u>Step-by-step explanation:</u>

Order does not matter so it is a Combination.

There are 14 men and we are going to choose 12 --> ₁₄C₁₂

There are 27 people and we are going to choose 12  --> ₂₇C₁₂

\dfrac{_{14}C_{12}}{_{27}C_{12}}\rightarrow\dfrac{14!}{(14-12)!}\div \dfrac{27!}{(27-12)!}=\large\boxed{\dfrac{7}{1,337,220}}

5 0
3 years ago
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