The mass of the first block will be three times the mass of the second block.
According to Newton's second law of motion, the force acting on a body is directly proportional to the acceleration as shown;
F is the acting force
m is the mass
a is the acceleration of the body
Given the following parameters
Constant force F = 1N
For the first block with the acceleration of "a"
1 = m₁a
a = m₁/1
m₁ = a .................1
For the second block, acceleration is thrice that of the first. This means;
F = m(3a)
1 = 3ma
..........................2
Divide both equations
From the calculation, we can conclude that the mass of the first block will be three times the mass of the second block.
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A). balanced force
b). unbalanced force
There's no such thing as either of these. A group of two or more forces can be balanced or unbalanced. A single force can't be.
c). gravitational force ... doesn't cause an object to move in a circle;
Drop a stone from the roof of a tall building and watch it fall.
It goes straight down, not in a circle.
d). centripetal force ... force directed toward the center of a circle,
causes an object to move in a circle.
Answer:
Explanation:
The formula for potential energy is:
where <em>m </em>is the mass, <em>g</em> is the gravitational acceleration, and <em>h</em> is the height.
The mass of the book is 0.4 kilograms. The gravitational acceleration on Earth is 9.8 m/s². The height of the book is 2 meters.
Substitute the values into the formula.
Multiply the first two numbers.
- 0.4 kg*9.8 m/s²= 3.92 kg*m/s²
- If we convert the units now, the problem will be much easier later on.
- 1 kg*m/s² is equal to 1 Newton. So, our answer of 3.92 kg*m/s² is equal to 3.92 N
Multiply.
- 3.92 N* 2 m=7.84 N*m
- 1 Newton meter is equal to 1 Joule (this is why we converted the units).
- Our answer is equal to<u> 7.84 Joules.</u>
The period of a spring-cart system motion when the system is in orbit inside the international space station will not change because in conditions of weightlessness it is not possible to measure the mass of a body from its weight and the period depends on the mass of the body.
Answer:
<h2>0.61 Hz</h2>
Explanation:
A Simple pendulum has length , then it's frequency is given by =
Frequency of a pendulum is the inverse of it's Time period. It denotes the number of cycles the pendulum completes in unit time.
For the given pendulum, length = , =
∴ Frequency of Simple pendulum = 0.61 Hz