Question

A train started at rest with acceleration of 0.50 m/s^2 and was in motion with constant acceleration for 25 s. How far did it go during acceleratin motion?

Answer 1

Answer:

156.25 m

Explanation:

Given Acceleration, a = 0.50 m/s²

Time, t = 25 s

u = 0 m/s as trains starts from rest

Distance, s = ?

Using the Equation of motion  as:

$s=ut+\frac {1}{2}at^2$

t = Time taken

u = Initial velocity

s = Displacement

a = Acceleration

Applying the values as:

$s=ut+\frac{1}{2}at^2\\\Rightarrow s=0\times 25+\frac{1}{2}\times 0.50\times 25^2\\\Rightarrow s=0+0.5\times \frac{625}{2}\\\Rightarrow s=156.25\ m$

The train will go 156.25 m far.