By using the coefficient of linear expansion, the increase in the length of the metal plate is by 0.015m and in the area is by 0.3074
.
The rate of change in length of a metal per degree change in temperature is known as the coefficient of linear expansion.
Given:
Coefficient of linear expansion, α = 29 x 
/k
Length, L1 = 10m
T1 = 25℃
T2 = 78℃
ΔT = 78 – 25 = 53℃
To find:
Change in length (ΔL) and area (ΔA) of metal plate = ?
Formula:
ΔL = α L1 ΔT
ΔA = A1 2 α ΔT
Calculations:
ΔL = 29 x x 10 x 53
ΔL = 0.01537m
ΔA = 100 x 2 x 29 x x 53
ΔA = 0.3074
A2 = 100.3074
Result:
The increase in the length and area is by 0.015m and 0.3074 respectively.
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Answer:
velocity in problems per hour = 4 per hour
so correct option is b. 4 per hour
Explanation:
given data
worked on homework time = 1.5 hour
completed = 6 problems
to find out
What is the velocity in problems per hour
solution
we know that Shirley solve complete 6 accounting homework problem in 1.5 hour so her velocity in problems per hour will be as
velocity in problems per hour = 
..................1
put here value we will get
velocity in problems per hour = 
velocity in problems per hour = 4 per hour
so correct option is b. 4 per hour
Answer:
The rate of change of the shadow length of a person is 2.692 ft/s
Solution:
As per the question:
Height of a person, H = 20 ft
Height of a person, h = 7 ft
Rate = 5 ft/s
Now,
From Fig.1:
b = person's distance from the lamp post
a = shadow length
Also, from the similarity of the triangles, we can write:
Differentiating the above eqn w.r.t t:
Now, we know that:
Rate = 
Thus
