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Delicious77 [7]
2 years ago
9

How do i do this- my brain has ✨evaporated✨

Mathematics
1 answer:
worty [1.4K]2 years ago
4 0

Answer:

lol

Step-by-step explanation:

im not even sure try using google

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N is an integer s=1/2 n(n+1) prove that 8s + 1 is an odd square number
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s=\frac{1}{2}n(n+1) \\ \\
8s+1=8 \times \frac{1}{2}n(n+1)+1=4n(n+1)+1=4n^2+4n+1=(2n+1)^2

n is an integer, so 2n+1 is also an integer. 8s+1 is equal to the square of 2n+1, so it's a square number.

2n+1 is an odd integer for any value of n. The square of an odd integer is always an odd integer. Therefore 8s+1=(2n+1)² is odd.

8s+1 is an odd square number.
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Step-by-step explanation:

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