I believe it is “runs on parallel circuits”! my bad if incorrect
Answer:
(a) k = 30.33 N/m
(b) a = 9.8 m/s²
Explanation:
First, we need to find the force acting on the bungee jumper. Since, this is a free fall motion. Therefore, the force must be equal to the weight of jumper:
F = W = mg
F = (65 kg)(9.8 m/s²)
F = 637 N
(a)
Now applying Hooke's Law:
F = k Δx
where,
k = spring constant = ?
Δx = change in length of bungee cord = 33 m - 12 m = 21 m
Therefore,
637 N = k(21 m)
k = 637 N/21 m
<u>k = 30.33 N/m</u>
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(b)
Since, this is free fall motion. Thus, the maximum acceleration will be the acceleration due to gravity.
a = g
<u>a = 9.8 m/s²</u>
No, the car travels 1 metre in 5s at the start which is 0.2m/s, while the second meter it travels one metre in 8 seconds which is 0.125 m/s, the speed changes therefore it is not constant during the two metres the car travels
The answer is b increases in increase of mass because the heavier the object is the more gravitional pull it will have. For example, what will fall faster? A 1 pound object or a 10 pound obect.
