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Ann [662]
3 years ago
8

Which factor does not affect the resistance of a material?

Physics
2 answers:
34kurt3 years ago
5 0

the best answer is b

Makovka662 [10]3 years ago
4 0

Answer: The correct answer is option B.

Explanation:

Resistance is the property of the material which resists the flow of current.

The expression for the resistance is as follows:

R=\frac{\rho l}{A}

Here, \rho is the density of the wire, l is the length of the wire and A is the area of the cross section of the wire.

The resistance of the wire depends on the length of the wire, area of the cross section of the wire and the temperature.

The thicker wire has less resistance. The thinner wire has more resistance.

The longer wire has more resistance in comparison to the shorter wire in length. The resistance of the wire increases with increase in temperature.

The resistance does not depend on the weight of the wire.

Therefore, the correct option is weight.

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Radio communications were severely Distributed last week And the local newspaper says that solar activity is to blame . Which ty
Juliette [100K]

Answer:

Solar Flares and Prominences

Explanation:

    The sun is source of light and heat energy and it supports life on earth because sun is the primary source of energy. But sun is also a star and is a glowing ball of hot gases mostly hydrogen and helium. There are so many activity that takes place on surface of sun. But the two activity solar flare and prominences affect the radio communication.

Solar Flare  are electromagnetic energy built up in the sun atmosphere .These energy travel with the speed of light and affect outer atmosphere of earth. These increased level of X rays and ultraviolet rays ions the layer of ionosphere which becomes superionised. thus causing destructive interference.

The radio waves travel in ionosphere and  frequently collide with electron lose energy and completely blackout.

Prominence is defined as gaseous cloud of calcium,hydrogen and other gases floating above sun chromosphere and emit violently particularly near sunspots sometimes travel through space and affect radio communication.

8 0
4 years ago
How much larger is the diameter of Jupiter compared to the diameter of Saturn?
allsm [11]
Really long we’ll not long but far in distance
5 0
3 years ago
What happens to light when it changes speed?
Brut [27]
Hey there!

When light changes speed, it REFRACTS.
Your answer is going to be option C.

Hope this helps you.
Have a great day!
5 0
3 years ago
I’m not sure how to solve this
spayn [35]

Answer:

Option 10. 169.118 J/KgºC

Explanation:

From the question given above, the following data were obtained:

Change in temperature (ΔT) = 20 °C

Heat (Q) absorbed = 1.61 KJ

Mass of metal bar = 476 g

Specific heat capacity (C) of metal bar =?

Next, we shall convert 1.61 KJ to joule (J). This can be obtained as follow:

1 kJ = 1000 J

Therefore,

1.61 KJ = 1.61 KJ × 1000 J / 1 kJ

1.61 KJ = 1610 J

Next, we shall convert 476 g to Kg. This can be obtained as follow:

1000 g = 1 Kg

Therefore,

476 g = 476 g × 1 Kg / 1000 g

476 g = 0.476 Kg

Finally, we shall determine the specific heat capacity of the metal bar. This can be obtained as follow:

Change in temperature (ΔT) = 20 °C

Heat (Q) absorbed = 1610 J

Mass of metal bar = 0.476 Kg

Specific heat capacity (C) of metal bar =?

Q = MCΔT

1610 = 0.476 × C × 20

1610 = 9.52 × C

Divide both side by 9.52

C = 1610 / 9.52

C = 169.118 J/KgºC

Thus, the specific heat capacity of the metal bar is 169.118 J/KgºC

6 0
3 years ago
Find the speed of light in each of the following materials. (a) gallium phosphide m/s (b) carbon disulfide m/s (c) benzene
Oksanka [162]

Explanation:

We need to calculate the speed of light in each materials

(I). Gallium phosphide,

The index of refraction of Gallium phosphide is 3.50

Using formula of speed of light

v=\dfrac{c}{\mu}....(I)

Where, \mu = index of refraction

c = speed of light

Put the value into the formula

v=\dfrac{3\times10^{8}}{3.50}

v=8.6\times10^{7}\ m/s

(II) Carbon disulfide,

The index of refraction of Gallium phosphide is 1.63

Put the value in the equation (I)

v=\dfrac{3\times10^{8}}{1.63}

v=1.8\times10^{8}\ m/s

(III). Benzene,

The index of refraction of Gallium phosphide is 1.50

Put the value in the equation (I)

v=\dfrac{3\times10^{8}}{1.50}

v=2\times10^{8}\ m/s

Hence, This is the required solution.

7 0
3 years ago
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