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3 years ago

Which factor does not affect the resistance of a material?

Physics

2 answers:

34kurt3 years ago

5 0

the best answer is b

Makovka662 [10]3 years ago

4 0

Answer: The correct answer is option B.

Explanation:

Resistance is the property of the material which resists the flow of current.

The expression for the resistance is as follows:

$R=\frac{\rho l}{A}$

Here, $\rho$ is the density of the wire, l is the length of the wire and A is the area of the cross section of the wire.

The resistance of the wire depends on the length of the wire, area of the cross section of the wire and the temperature.

The thicker wire has less resistance. The thinner wire has more resistance.

The longer wire has more resistance in comparison to the shorter wire in length. The resistance of the wire increases with increase in temperature.

The resistance does not depend on the weight of the wire.

Therefore, the correct option is weight.

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1. It takes a 25 N force to push a 250 N box across the floor.

Fed [463]

Answer:

A:- 50 J

B:- 500 J

Explanation:

a) Given that a 25 N force is applied to move the box. Also the floor is having friction surface.

So in order to move the box, the floor should have friction of atleast 25 N.

∴ friction = 25 N

Work done = force * displacement of box

Given, the box is moved 2 m across the floor

So, Work done = friction * 2 m

= 25 * 2

= 50 J

b) Given, the box is having weight of 250 N weight

Gravitational force is acting on the box which is equal to (mass * gravity)

∴ Force = 250 N

The box is lifted 2 m above the floor.

So, displacement = 2 m

Work done = force * displacement of box

Work done = 250 * 2

= 500 J

5 0

3 years ago

The diameter of a 12-gauge copper wire is 0.081 in. The maximum safe current it can 17) carry (in order to prevent fire danger i

Soloha48 [4]

Answer:

0.44m/s

Explanation:

drift velocity=I/nAq

diameter 12 gauge

wire=0.081inches=0.081*2.5=0.2025cm radius=0.10125cm area=pi*R^2 =20/8.5*10^22*3.14*0.10125^2*10^-4*1.6*10^-19*

V = 0.44m/s

6 0

4 years ago

A batter hits two baseballs with the same force.One hits the ground near third base.The other is a home run out of the park.Wher

andrezito [222]

The formula for work is:

W = F * d Where W is work, F is Force, and d is distance.

Without doing any math, it can be seen from the equation that work is directly proportional to the force applied and the distance it travels. The homerun hit both traveled more distance and had a grater force applied to it in order to achieve this distance (assuming both baseballs weighed the same). Based on this reasoning, it is valid to conclude that the baseball which was a homerun was the hit that accomplished more work.

5 0

4 years ago

Find time when boy catches the girl or when they are at their closest separation..

soldier1979 [14.2K]

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\implies{Time=10\:sec\:and\:30\:sec}}} \\\\$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}} \\ \\$

$\green{\underline{\bold{Given :}}} \\ \\ \:\:\:\: \bullet\:\:\tt\red{ Velocity \: of \: boy = 50 \: m/s} \\ \\ \:\:\:\: \bullet\:\: \tt\orange{Velocity \: of \: girl = 30 \: m/s }\\ \\ \:\:\:\: \bullet\:\:\tt\green{ Acceleration \: of \: boy = {1 \: m/s}^{2}} \\ \\ \:\:\:\:\bullet\:\: \tt\blue{Acceleration \: of \:girl= {2\: m/s}^{2} }\\ \\ \:\:\:\: \bullet \:\:\tt\purple{Sepration \: between \: them = 150 \: m }\\ \\ \\ \red{\underline{\bold{To \: Find :}}} \\ \\ \:\:\:\: \bullet\:\: \tt\blue{Time \: taken \: to \: catch \: the \: girl }\\$

<u>According to given question</u> :

$\\ \green{\star} \: \text{Using \: relative \: motion \: method} \\ \\ \green{ \circ} \: \tt Net \: velocity = 50 - 30 = 20 \: m/s \\ \\ \green{ \circ} \: \tt Net \: acceleration = 1 - 2 = - 1\: m /{s}^{2} \\\\ \\ \star\:\bold\red{\underline{\:As \: we \: know \: that\:}} \\\\ \tt\purple{: \implies s = ut + \frac{1}{2} {at}^{2}} \\ \\ \tt\green{: \implies 150 = 20 \times t + \frac{1}{2} \times -1 \times {t}^{2}} \\ \\ \tt\purple{: \implies 300 = 40t - {t}^{2}} \\ \\ \tt\green{: \implies {t}^{2} - 40t + 300 = 0} \\ \\ \tt\purple{: \implies t = \frac{ - ( - 40) \pm\sqrt{ { (- 40)}^{2} - 4 \times 1 \times 300} }{2 \times 1} }\\ \\ \tt\green{: \implies t = \frac{40 \pm \sqrt{1600 - 1200} }{2} }\\ \\ \tt\purple{: \implies t = \frac{40 \pm 20}{2} }\\ \\ \green{\tt: \implies t = 10 \: sec \: and \: 30 \: sec}$

7 0

3 years ago

Two charged particles move in the same direction with respect to the same magnetic field. Particle 1 travels seven times faster

alexgriva [62]

Answer:

|q1|/|q2| = 1/7

Explanation:

Particle 1 experiences a force F1 due to the magnetic field, B:

F1 = |q1|*v1*B

Particle 2 experiences a force F2 due to the magnetic field, B:

F2 = |q2|*v2*B

We're given that:

v1 = 7v2

Also, the force experience by both particles are equal:

F1 = F2

=> |q1|*v1*B = |q2|*v2*B

|q1|/|q2| = v2/v1

=> |q1|/|q2| = v2/7v2

=> |q1|/|q2| = 1/7

7 0

4 years ago

Read 2 more answers