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Ann [662]
3 years ago
8

Which factor does not affect the resistance of a material?

Physics
2 answers:
34kurt3 years ago
5 0

the best answer is b

Makovka662 [10]3 years ago
4 0

Answer: The correct answer is option B.

Explanation:

Resistance is the property of the material which resists the flow of current.

The expression for the resistance is as follows:

R=\frac{\rho l}{A}

Here, \rho is the density of the wire, l is the length of the wire and A is the area of the cross section of the wire.

The resistance of the wire depends on the length of the wire, area of the cross section of the wire and the temperature.

The thicker wire has less resistance. The thinner wire has more resistance.

The longer wire has more resistance in comparison to the shorter wire in length. The resistance of the wire increases with increase in temperature.

The resistance does not depend on the weight of the wire.

Therefore, the correct option is weight.

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That's going to depend on the mass of the crate. They'll be able to push a crate full of pingpong balls really high, but they may not be able to even budge the crate at all if it's full of bricks.
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A projectile is fired straight upward from the Earth's surface at the South Pole with an initial speed equal to one third the es
7nadin3 [17]
What is the question? if you are looking for the initial velocity of the projectile, then V escape of Earth = 11.2 km / s. divided by three
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3 0
3 years ago
"A uniform cylinder of mass M and radius R is rolling without slipping. The velocity of its center of mass is v. What is the cyl
Goshia [24]

Answer:

Explanation:

Given

mass of cylinder is M

radius R

velocity of center of mass is v

As there is no slipping therefore cylinder will rotate as well as translate

Moment of inertia of cylinder I=\frac{MR^2}{2}

Kinetic Energy of cylinder K.E.=\frac{1}{2}Mv^2

Rotational energy R.E.=\frac{1}{2}I\omega ^2

for rolling

v=\omega \times r

where \omega =angular\ velocity\ of\ cylinder

R.E.=\frac{1}{2}\times \frac{MR^2}{2}\times (\frac{v}{R})^2=\frac{1}{4}Mv^2

Total kinetic Energy =\frac{1}{2}Mv^2+\frac{1}{4}Mv^2=\frac{3}{4}Mv^2

6 0
3 years ago
What is the net work doneon the object over the distance shown?
GuDViN [60]

A)F_0d

Explanation

If you graph the force on an object as a function of the position of that object, then the area under the curve will equal the work done on that object, so we need to find the area under the function to find the work

Step 1

find the area under the function.

so

Area:

\text{Area}=rec\tan gle_{green}+triangle_{gren}-triangle_{red}\begin{gathered} \text{the area of a rectangle is given by} \\ A_{rec}=lenght\cdot widht \\ \text{and} \\ \text{the area of a triangle is given by:} \\ A_{tr}=\frac{base\cdot height}{2} \end{gathered}

so

\begin{gathered} \text{Area}=rec\tan gle_{green}+triangle_{gren}-triangle_{red} \\ \text{replace} \\ \text{Area}=(F_0\cdot d)+\frac{(F_0\cdot d)}{2}-\frac{(F_0\cdot d)}{2} \\ \text{Area}=(F_0\cdot d) \\ Area=F_0d \end{gathered}

therefore, the answer is

A)F_0d

I hope this helps you

4 0
1 year ago
A weight suspended from a spring is seen to bob up and down over a distance of 20 cm triply each second. What is the period? Wha
Kisachek [45]

Answer:

1) Hence, the period is 0.33 s.

2) The amplitude is 10 cm.

Explanation:

1) The period is given by:

T = \frac{1}{f}

Where:

f: is the frequency = 3 bob up and down each second = 3 s⁻¹ = 3 Hz

T = \frac{1}{f} = \frac{1}{3 Hz} = 0.33 s

Hence, the period is 0.33 s.

2) The amplitude is the distance between the equilibrium position and the maximum position traveled by the spring. Since the spring is moving up and down over a distance of 20 cm, then the amplitude is:          

A = \frac{20 cm}{2} = 10 cm  

Therefore, the amplitude is 10 cm.          

I hope it helps you!                    

5 0
3 years ago
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