<span>1. Suppose that a family has an equally likely chance of having a cat or a dog. If they have two pets, they could have 1 dog and 1 cat, they could have 2 dogs, or they could have 2 cats.
What is the theoretical probability that the family has two dogs or two cats?
25% chance
</span><span>2. Describe how to use two coins to simulate which two pets the family has.
</span>
You could use the coins to simulate which pet the family has by flipping them and having head be dog and tails be cat (or vice-versa).
<span>3. Flip both coins 50 times and record your data in a table like the one below.
</span><span>Based on your data, what is the experimental probability that the family has two dogs or two cats?
</span>
Based on the results, I concluded that for Heads, Heads (which could be dogs or cats) there was a 24% chance and for Tails, Tails there was a 26% chance
<span>4. If the family has three pets, what is the theoretical probability that they have three dogs or three cats?
1/8 chance (accidentally messed up there) or 12.5%
</span><span>5. How could you change the simulation to generate data for three pets?
</span><span>
To flip 3 coins and add more spots on the chart.
I hope that this helps because it took a while to write out. If it does, please rate as Brainliest
</span>
Answer:
The correct answer is A
Step-by-step explanation:
We want to determine the decimal equivalence of 
.
We perform the long division as shown in the attachment.
Note that in carry out the long division, the denominator which is 3, will be outside the long division sign, while the numerator which is 
, will be inside the long division sign.
We see that the quotient of our long division is 
.
We can rewrite this as
Therefore 
.
Answer:
its D i do belive
Step-by-step explanation:
Https://tex.z-dn.net/?f=+%5Cfrac%7B8%7D%7B64%7D+%3D+%5Cfrac%7B2%7D%7Bx%7D++%5C%5C++%5C%5C+8x%3D128+%5C%5C++%5C%5C+x%3D16
