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finlep [7]
3 years ago
6

Among the following, which atom is most likely to form an ion with a charge of 2+?

Chemistry
1 answer:
Zigmanuir [339]3 years ago
5 0

Answer:

C. Ca.

Explanation:

The atom loses or gains electrons forming anion or cation to reach stability (fill the outermost shell of the electron levels).

When atom gains electrons forms anions with negative charge.

While, when atom loses electrons forms cations with positive charge.

A. O:

O atom has 8 electrons in its nucleus and gains 2 electrons to reach stability (10 electrons, configuration of Ne).

<em>So, it forms O²⁻.</em>

<em></em>

B. AI:

Al atom has 13 electrons in its nucleus and loses 3 electrons to reach stability (10 electrons, configuration of Ne).

<em>So, it forms Al³⁺.</em>

<em></em>

C. Ca:

Ca atom has 12 electrons in its nucleus and loses 2 electrons to reach stability (10 electrons, configuration of Ne).

<em>So, it forms Ca²⁺.</em>

<em></em>

D. Na:

Na atom has 11 electrons in its nucleus and loses 1 electron to reach stability (10 electrons, configuration of Ne).

<em>So, it forms Na⁺.</em>

<em></em>

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A fixed amount of gas at 25.0°C occupies a volume of 10.0 L when the pressure is 667 torr. Use Boyle's law to calculate the pres
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The pressure, when the volume is reduced to 7.88L, is 846 torr (option A)

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Step 1: Data given

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Step 2: Boyle's law

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A molecular orbital that decreases the electron density between two nuclei is said to be <u>antibonding.</u>

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An asterisk (sigma*) is placed next to the corresponding kind of molecular orbital to indicate an antibonding orbital. The antibonding orbital known as * would be connected to sigma orbitals, as well as antibonding pi orbitals are known as \pi* orbitals.

Therefore,  molecular orbital that decreases the electron density between two nuclei is said to be <u>antibonding.</u>

<u></u>

Hence, the correct answer will be option (b)

<u />

To know more about molecular orbital

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