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klemol [59]
3 years ago
14

Calculate the pressure in Pascals when a box with a weight force of 294 Newtons is placed on its base which measures 24cm by 12c

m.
Chemistry
1 answer:
saul85 [17]3 years ago
5 0

Answer:

force = 294 N

Area of base = 0.24 m × 0.12 m = 0.288 m^2

Pressure applied = Force ÷ Area

=》P = 294 ÷ 0.288

=》P = 1020.83 pascals

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Tcecarenko [31]
The answer should be B
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All of the following show a periodic pattern except
AlekseyPX
<span>A. the dog ate everyone of his play toys</span>
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If the density of an object is 5 g/cm3 and it takes up 7 cm3 of space, calculate the mass?
statuscvo [17]

Answer:

<h2>The answer is option A</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume of object = 7 cm³

density = 5 g/cm³

The mass of the object is

mass = 5 × 7

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8 0
3 years ago
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Drupady [299]
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4 0
3 years ago
Methanol can be produced by the following reaction: CO(g) 2 H2(g) CH3OH(g). How is the rate of disappearance of hydrogen gas rel
belka [17]

Answer:

r_{H_2}=-2r_{CH_3OH}

Explanation:

Hello!

In this case, for the reaction:

CO(g)+ 2 H_2(g) \rightarrow CH_3OH(g)

In such a way, via the rate proportions, that is written considering the stoichiometric coefficients, we obtain:

\frac{1}{-1} r_{CO}=\frac{1}{-2} r_{H_2}=\frac{1}{1} r_{CH_3OH}

Whereas the reactants, CO and H2 have negative stoichiometric coefficients; therefore the rate of disappearance of hydrogen gas is related to the rate of appearance of methanol as shown below:

\frac{1}{-2} r_{H_2}=\frac{1}{1} r_{CH_3OH}\\\\r_{H_2}=\frac{-2}{1} r_{CH_3OH}\\\\r_{H_2}=-2r_{CH_3OH}

Which means that the rate of disappearance of hydrogen gas is negative and the rate of appearance of methanol is positive.

Regards!

7 0
3 years ago
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