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LUCKY_DIMON [66]
3 years ago
8

Given the reaction:CO2 + 6 H2O==> C6H12O6 + 6 O2

Chemistry
2 answers:
kari74 [83]3 years ago
5 0
For every 1 mole of C6H12O6, you need 6 moles of water. Multiply the 2.5 moles you are trying to make by the 6 of water you need, and 4) 15 is your answer.
Montano1993 [528]3 years ago
4 0
For every 6 H2O molecules, you can produce 1 C6H12O6 molecule.

Therefore, if you needed to make 2.5 moles of C6H12O6, you would need:
2.5mol C6H12O6*(6mol H2O/1mol C6H12O6)= 15mol H2O

(4) 15 is the correct answer.

Hope this would help~
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What is the volume of a weather balloon that has 39 grams of helium with a density 0.017 g/mL?
olchik [2.2K]

Answer:

<h3>The answer is 235.29 mL</h3>

Explanation:

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volume =  \frac{mass}{density}  \\

From the question.

density = 0.017 g/mL

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We have

volume =  \frac{4}{0.017}  \\  = 235.2941176...

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Hope this helps you

4 0
2 years ago
Suppose 0.981 g of iron (II) iodide is dissolved in 150. mL of a 35.0 m M aqueous solution of silver nitrate. Calculate the fina
yaroslaw [1]

Answer:

Final molarity of iodide ion C(I-) = 0.0143M

Explanation:

n = (m(FeI(2)))/(M(FeI(2))

Molar mass of FeI(3) = 55.85+(127 x 2) = 309.85g/mol

So n = 0.981/309.85 = 0.0031 mol

V(solution) = 150mL = 0.15L

C(AgNO3) = 35mM = 0.035M = 0.035m/L

n(AgNO3) = C(AgNO3) x V(solution)

= 0.035 x 0.15 = 0.00525 mol

(AgNO3) + FeI(3) = AgI(3) + FeNO3

So, n(FeI(3)) excess = 0.00525 - 0.0031 = 0.00215mol

C(I-) = C(FeI(3)) = [n(FeI(3)) excess]/ [V(solution)] = 0.00215/0.15 = 0.0143mol/L or 0.0143M

8 0
3 years ago
The correct name for hno2 is ________. nitrous acid hyponitrous acid nitric acid pernitric acid hydrogen nitrate
balu736 [363]
Nitrous Acid.

Hyponitrous acid: H2N2O2

Nitric acid: HNO3

Pernitric acid: HNO


4 0
2 years ago
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