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LUCKY_DIMON [66]
3 years ago
8

Given the reaction:CO2 + 6 H2O==> C6H12O6 + 6 O2

Chemistry
2 answers:
kari74 [83]3 years ago
5 0
For every 1 mole of C6H12O6, you need 6 moles of water. Multiply the 2.5 moles you are trying to make by the 6 of water you need, and 4) 15 is your answer.
Montano1993 [528]3 years ago
4 0
For every 6 H2O molecules, you can produce 1 C6H12O6 molecule.

Therefore, if you needed to make 2.5 moles of C6H12O6, you would need:
2.5mol C6H12O6*(6mol H2O/1mol C6H12O6)= 15mol H2O

(4) 15 is the correct answer.

Hope this would help~
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The  oxidation state is zero for Fe (s)

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What is corona virus explain plss
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Read 2 more answers
A certain gas is found in the exhaust of automobiles and power plants. Consider a 1.53 L sample of a gas at a pressure of 5.6 x
Olegator [25]

The new volume of the gas that has an initial pressure of 5.6 x 10⁵ Pa is 5.7L. Details about volume of the gas can be found below.

<h3>How to calculate volume?</h3>

The volume of a gas can be calculated using the Boyle's law equation as follows:

P1V1 = P2V2

Where;

  • P1 = initial pressure
  • P2 = final pressure
  • V1 = initial volume
  • V2 = final volume

1.53 × 5.6 × 10⁵ = 1.5 × 10⁵ × V2

8.568 × 10⁵ = 1.5 × 10⁵V2

V2 = 8.57 × 10⁵ ÷ 1.5 × 10⁵

V2 = 5.7L

Therefore, the new volume of the gas that has an initial pressure of 5.6 x 10⁵ Pa is 5.7L.

Learn more about volume at: brainly.com/question/12357202

#SPJ1

6 0
2 years ago
3 Apply Use context clues to write your own definitions for the words definite and occupy.
motikmotik

Answer:

Explanation:

own definitions for the words definite and occupy.

Example sentence

Solid is the state of matter that has a definite shape and volume.

definite:

__________

Example sentence

A larger container will allow a gas to occupy more space.

occupy:

3 0
2 years ago
When 8.00x10^22 molecules of ammonia react with 7.00x10^22 molecules of oxygen according to the chemical equation shown below, h
Pavel [41]
NH₃:

N = 8*10²²
NA = 6.02*10²³

n = N/NA = 8*10²²/6.02*10²³ ≈ 1.33*10⁻¹=0.133mol

O₂:

N=7*10²²
NA = 6.02*10²³

n = N/NA = 7*10²²/6.02*10²³ = 1.16*10⁻¹=0.116mol

4NH₃                   <span>+                        3O</span>₂                      ⇒<span>          2N</span>₂<span> + 6H</span>₂<span>O
</span>4mol                     :                        3mol                   :             2mol
0.133mol             :                        0.116mol           :             0,0665mol
limiting reactant

N₂:

n = 0.0665mol
M = 28g/mol

m = n*M = 0.0665mol*28g/mol = <u>1,862g</u>
6 0
4 years ago
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