Answer:
<em>The correct option is B. Alleles</em>
Explanation:
The punnet square can be described as a diagram which shows the outcomes of a cross. A punnet square will help us know what will be the probability for a particular trait to occur in the offsprings.
Genes might have the same or different alleles. If the alleles for a gene are similar in an organism, the organism is said to be homozygous for the trait. If the alleles are different, then the organism is termed as heterozygous.
A dominant allele is the one which which suppresses the effect of the recessive allele. A recessive allele gets masked by a dominant allele.
The effect Colchicine might have on dividing cells is that the duplicated chromosomes might not be able to segregate into daughter nuclei.
Colchicine is an alkaloid that attaches to tubulin and prevents it from polymerization to microtubules. As we know that Microtubules are a component of the cytoskeleton of a cell that aids in molecular mobility inside the cell.
During cell division, chromatin condenses into chromosomes, which are then connected to microtubules. The chromosomes are separated into daughter cells by microtubules.
When these cells are treated with colchicine, tubulin polymerization to microtubules may not occur, and the chromosomes containing daughter nucleic might not be separated.
Learn more about chromosomes here:
brainly.com/question/2583209?referrer=searchResults
Answer:The based on this information interaction between these two species can best be described as COMPETITION. Correct option is B
Explanation:
Competition occurs between two species that shares the same requirements ( especially food) for survival.
Both the Western Toad and the Bull Frog has a similar niche because they require the same type of food (beetles, bees, and small aquatic insects) to survive in the environment of Arroyo Seco. Only one of the species will coexist in that environment and it's usually the survival of the fittest.
This explains the competitive exclusion principle proposed by Georgii Gause in 1934.
Answer:
1. Allele frequency of b = 0.09 (or 9%)
2. Allele frequency of B = 0.91 (0.91%)
3. Genotype frequency of BB = 0.8281 (or 82.81%)
4. Genotype frequency of Bb = 0.1638 (or 16.38%)
Explanation:
Given that:
p = the frequency of the dominant allele (represented here by B) = 0.91
q = the frequency of the recessive allele (represented here by b) = 0.09
For a population in genetic equilibrium:
p + q = 1.0 (The sum of the frequencies of both alleles is 100%.)
(p + q)^2 = 1
Therefore:
p^2 + 2pq + q^2 = 1
in which:
p^2 = frequency of BB (homozygous dominant)
2pq = frequency of Bb (heterozygous)
q^2 = frequency of bb (homozygous recessive)
p^2 = 0.91^2 = 0.8281
2pq = 2(0.91)(0.9) = 0.1638
