Answer:
980,100
Explanation:
let the recessive condition (aa) be represented as q² which is the genotypic frequency = 100/1,000,000 = 0.0001
allelic frequency of a = q = √q² = √0.0001 = 0.01. thus q = 0.01
From the formula p + q = 1 where p is the allelic frequency of A.
since q = 0.01
p = 1 - 0.01 = 0.99. The allelic frequency of A (p) = 0.99
p² = 0.99² = 0.9801. Genotypic frequency of AA= 0.9801
= 0.9801 x 1,000,000 = 980,100 individuals with AA (homozygous normal)
For 2pq genotypic frequency for hetrozygous (Aa).
Using the formula p² + 2pq + q² = 1. Since p² = 0.9801 and q² = 0.0001
2pq = 1 - (p² + q²)
= 1 - (0.9801 + 0.0001)
= 1 - (0.9802)
= 0.0198 = 0.0198 x 1,000,000 = 19,800 individuals with Aa
Answer:
a&b blood
Explanation:
because it needs to be half mother and a father blood that why my answer is a&b blood
Answer:
Due to its spreading nature.
Explanation:
Transboundary environmental threats like pollution is a problem for both parties i. e. one that is producing pollution and the other which is not producing it, because pollution can't remain at one place and spread from one part to another part of the earth due to open environment. So due to its spreading, it affected both the producing and non-producing parties.
I believe the answer to this question is cellular respiration
I honestly think that a or d would be the best options. I would start with D and if that doesn't work try a.
