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Tasya [4]
3 years ago
14

I need help ASAP! 10 points!

Chemistry
2 answers:
Nina [5.8K]3 years ago
7 0

Answer:

The answer to this question is ( a )

Explanation:

olga_2 [115]3 years ago
4 0
Ionic: transfer of electrons covalent: sharing of electrons
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In the reaction N2 + 3H2 → 2NH3, what is the mole ratio of hydrogen to nitrogen?
uranmaximum [27]

Answer: The mole ratio of hydrogen to nitrogen is 3 mole: 1 mole, 3:1

Explanation:

•Mole ratios are determined using the coefficients of the substances in the balanced chemical equation. •Each coefficient represents the number of mole of each substance in the chemical reaction.

•The mole ratio can be determined by first writing out a balanced chemical equation for the reaction.

For this reaction the balanced chemical equation is

N2(g) + 3H2(g) ----> 2NH3(g)

1mol:3mol : 2mol

From the equation we can see that 1 mole of N2(g) reacts with 3 moles of H2(g) or 3 moles of H2(g) react with 1 mole of N2(g) to produce 2 moles of NH3(g).

Therefore, the mole ratio of hydrogen to nitrogen is 3 mole: 1 mole, 3:1

7 0
3 years ago
Ammonia (NH3) is one of the most common chemicals produced in the united states. it is used to make fertilizer and other product
Greeley [361]

Answer:

a) N2 is the limiting reactant

b) <u>1215.9 grams NH3</u>

<u>c) 2283.6 grams H2</u>

Explanation:

Step 1: Data given

Mass of N2 = 1000 grams

Molar mass N2 = 28 g/mol

Mass of H2 = 2500 grams

Molar mass H2 = 2.02 g/mol

Step 2: The balanced equation

N2(g) +3H2(g) → 2NH3(g)

Step 3: Calculate moles N2

Moles N2 = mass N2 / molar mass N2

Moles N2 = 1000 grams / 28.0 g/mol

Moles N2 = 35.7 moles

Step 4: Calculate moles H2

Moles H2 = 2500 grams / 2.02 g/mol

Moles H2 = 1237.6 moles

Step 5: Calculate limiting reactant

For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3

<u>N2 is the limiting reactant</u>. There will be consumed 35.7 moles.

H2 is in excess. There will react 3*35.7 = 107.1 moles

There will remain 1237.6 - 107.1= 1130.5 moles H2

This is 1130.5 * 2.2 = <u>2283.6 grams H2</u>

Step 6: Calculate moles NH3

For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3

For  35.7 moles N2 we'll have 2*35.7 = 71.4 moles NH3

Step 7: Calculate mass NH3

Mass NH3 = moles NH3 * molar mass NH3

Mass NH3 = 71.4 moles * 17.03 g/mol

Mass NH3 = <u>1215.9 grams NH3</u>

7 0
3 years ago
"Calculate the pH during the titration of 30.00 mL of 0.1000 M C3H7COOH(aq) with 0.1000 M LiOH(aq) after 29.9 mL of the base hav
Ivanshal [37]

Answer:

pH = 7.29

Explanation:

<em>Ka of butanoic acid is 1.54x10⁻⁵</em>

To obtain the pH of the solution you must use H-H equation for butanoic acid:

pH = pKa + log₁₀ [C₃H₇COO⁻] / [C₃H₇COOH]

Where pKa is defined as -log Ka = 4.81

Now, you need to find [C₃H₇COO⁻] and [C₃H₇COOH] concentrations (Also, you can find moles of each substance and replace them in the equation.

Butanoic acid reacts with LiOH, producing C₃H₇COO⁻, thus:

C₃H₇COOH + LiOH → C₃H₇COO⁻ + H₂O + Li⁺

Moles of both reactants, C₃H₇COOH and LiOH are:

C₃H₇COOH = 0.0300L ₓ (0.1000mol / L) = 0.003000moles of C₃H₇COOH

LiOH = 0.0299L ₓ (0.1000mol / L) = 0.00299 moles of LiOH.

That means moles of C₃H₇COO⁻ produced are <em>0.00299 moles</em>.

And moles of C₃H₇COOH that remains in solution are:

0.00300 - 0.00299 = <em>0.00001 moles of C₃H₇COOH</em>

Replacing in H-H equation:

pH = pKa + log₁₀ [C₃H₇COO⁻] / [C₃H₇COOH]

pH = 4.81 + log₁₀ [0.00299moles] / [0.00001moles]

<h3>pH = 7.29</h3>

7 0
3 years ago
Are elements, compounds, or both made up of small invisible particles?
son4ous [18]

I think both of them are but I really don't know


6 0
3 years ago
What is the ratio of the diffussion of Co2 and O2​
BartSMP [9]

Answer:

for me to be able to get to the office today and I will be in the office tomorrow and will be able the get time final

5 0
3 years ago
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