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2 years ago

What does the word "isohyet" mean?

Mathematics

1 answer:

stepan [7]2 years ago

5 0

Answer:

An isohyet is a line on a map which connects points that have the same amounts of precipitation in a given period or for a particular storm.

Step-by-step explanation:

You might be interested in

Is 9.058 greater than less than or equal to 9.24<br>

Crank

Answer:

9.058 is less than 9.24

Step-by-step explanation:

there is 0 in the tenth digit and there is 2 in the tenths digit so therefor, 9.058 is less than 9.24

Hope this helps:)

3 0

2 years ago

Read 2 more answers

Suppose that the length of a side of a cube X is uniformly distributed in the interval 9

Nastasia [14]

Answer:

$f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.$

Step-by-step explanation:

Given

$9 < x < 10$ --- interval

Required

The probability density of the volume of the cube

The volume of a cube is:

$v = x^3$

For a uniform distribution, we have:

$x \to U(a,b)$

and

$f(x) = \left \{ {{\frac{1}{b-a}\ a \le x \le b} \atop {0\ elsewhere}} \right.$

$9 < x < 10$ implies that:

$(a,b) = (9,10)$

So, we have:

$f(x) = \left \{ {{\frac{1}{10-9}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

Solve

$f(x) = \left \{ {{\frac{1}{1}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

$f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

Recall that:

$v = x^3$

Make x the subject

$x = v^\frac{1}{3}$

So, the cumulative density is:

$F(x) = P(x < v^\frac{1}{3})$

$f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$ becomes

$f(x) = \left \{ {{1\ 9 \le x \le v^\frac{1}{3} - 9} \atop {0\ elsewhere}} \right.$

The CDF is:

$F(x) = \int\limits^{v^\frac{1}{3}}_9 1\ dx$

Integrate

$F(x) = [v]\limits^{v^\frac{1}{3}}_9$

Expand

$F(x) = v^\frac{1}{3} - 9$

The density function of the volume F(v) is:

$F(v) = F'(x)$

Differentiate F(x) to give:

$F(x) = v^\frac{1}{3} - 9$

$F'(x) = \frac{1}{3}v^{\frac{1}{3}-1}$

$F'(x) = \frac{1}{3}v^{-\frac{2}{3}}$

$F(v) = \frac{1}{3}v^{-\frac{2}{3}}$

So:

$f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.$

8 0

2 years ago

Today, Barry wants to write at least 50 pages of his research paper. Barry wrote 18 pages this morning. Barry averages about 8 p

Sever21 [200]

Answer:

The answer is

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Rico ran a race that was 3 km long. how many meters did rico run?

pishuonlain [190]

3000 meters in total.

4 0

3 years ago

What is the answer!?!?!?

77julia77 [94]

The price for hardcover books is 1.50 and the price for paperback is .50

8 0

3 years ago