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3 years ago

What is 2.764 rounded to the nearest hundredth

Mathematics

2 answers:

kifflom [539]3 years ago

8 0

Answer:

2.76

Step-by-step explanation:

you only round up if it is a five or higher

Dafna11 [192]3 years ago

7 0

Answer:

Step-by-step explanation:

The thousandth digit is a 4. When you round it, it is under 5 so the 4 is dropped and the result is 2.76

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Y = 1/2x + 1: how do you graph the equation<br>

ipn [44]

Answer:

the right answer is x+1

Step-by-step explanation:

1/2x+1

therefore :

2×1/2x+1

x+1

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3 years ago

Display the set of data in a histogram.

VARVARA [1.3K]

Answer:

The answer to your question is the third histogram

Step-by-step explanation:

What we must check in a histogram is that the x-axis is represented the intervals and in the y-axis is represented the frequency.

The first histogram is incorrect just by observing the first bar, we notice that the correct frequency from 0 to 4 is 3, not 14. This histogram is incorrect.

Also, the second histogram is incorrect, the frequency of the first category is 3, not 12. This histogram is wrong.

The third histogram is correct because all the bars are in agreement with their frequencies.

The last histogram is incorrect, for example, the last frequency is 12, not 3.

4 0

3 years ago

How do I solve 3(x+5)=39

azamat

3(x+5)=39

3 * x + 3 * 5 = 39

3x + 15 = 39

3x = 39 - 15

3x= 24
x = 8

4 0

3 years ago

Read 2 more answers

What is the perimeter of a square with an area of 81 cm2

tatyana61 [14]

Answer:

36 cm

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

3. A ball was thrown into the air with an initial velocity of 72 feet per second. The height of the

timurjin [86]

Answer:

A. The maximum heigh is 81 feet

B. The ball will reach the maximum heiight at 2.25 seconds

C. The domain of the function is $t\in [0,4.5]$

D. The range of the function is $h(t)\in [0,81]$

E. 4.5 seconds

Step-by-step explanation:

A ball was thrown into the air with an initial velocity of 72 feet per second. The height of the ball after t seconds is represented by the equation:

$h= -16t^2 + 72t$

The maximum height will be at parabola's vertex. Find it:

$t_v=\dfrac{-b}{2a}\\ \\t_v=-\dfrac{72}{2\cdot (-16)}=\dfrac{72}{32}=\dfrac{9}{4}=2.25\\ \\h(t_v)=-16\cdot t_v^2+72\cdot t_v\\ \\h(2.25)=-16\cdot 2.25^2+72\cdot 2.25=81$

A. The maximum heigh is 81 feet

B. The ball will reach the maximum heiight at 2.25 seconds

C. Find where the parabola intersects the x-axis:

$h=0\Rightarrow -16t^2+72t=0\\ \\t(-16t+72)=0\\ \\t_1=0\ \text{or}\ 16t=72,\ t_2=\dfrac{9}{2}=4.5$

So, the domain of the function is $t\in [0,4.5]$

D. The range of the function is

$h(t)\in [0,81]$

E. The ball is at the air for 4.5 seconds

4 0

4 years ago