What is the perimeter of a square with an area of 81 cm2
2 answers:
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Answer:
Θ = 157.7°
Step-by-step explanation:
Given
cosΘ = - 0.925
Since cosΘ < 0 then Θ is in the second or third quadrant.
Since 0° ≤ Θ ≤ 180° then Θ is in the second quadrant. thus
Θ = (- 0.925) = 157.7° ← angle in second quadrant
By taking <span>logarithmic of base 10
∴ </span><span>
∴ x log 4 = log 64
∴
note: we don't need to write the base in case of the base =10
∴ The correct choice is
</span><span>x = log base 10 of 64, all over log base 10 of 4</span>