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3 years ago

What is 9/10 - 1/3 Closer to 0,1,1/2

Mathematics

2 answers:

AveGali [126]3 years ago

6 0

Answer:

1/2

Step-by-step explanation:

9/10-1/3=0.56666666666666666...

likoan [24]3 years ago

5 0

He is right I would go with his answer

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Find the digits in the tens place, in the hundredths place, and in the thousandths place for the following number 748.6291

tresset_1 [31]

Answer:

8 for tens, 9 for hundredths and thousandths is 1

Step-by-step explanation:

you can find the number by looking at the place of the numbers if it is tens look at the tens place which is the number eight as tens are 2 digit numbers

5 0

2 years ago

What is 1/2 divided by 4?

Natasha_Volkova [10]

1/2/4=1/2 x 1/4 = 1/8

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3 years ago

Read 2 more answers

complete each statement with the appropriate measurement or symbol. 48 c = (fill blank) qt , 96 oz (fill blank) 5 lb , 6 yd, 1 f

DochEvi [55]

Answer:

48 cub = 12 Qt

96 Oz > 5 lb

6 yd 1 ft = 9 ft

6 1/2 lb = 104 oz

Step-by-step explanation:

Use the below key formula to convert the units.

1 cub = 4 Quart

16 ounce = 1 lb

96 ounce = 6 lb

1 yd = 3 feet

6 yd 1 ft = 6*3 + 1 = 18 + 1 = 19 feet

Hope this will help you to understand.

Thank you.

6 0

3 years ago

Contestants in a dance-a-thon rest for the same amount of time every hour. A couple rests for 27 minutes In 3 hours. How long di

NeX [460]

Set up a ratio and solve for the missing value:

$\frac{27}{3} =\frac{x}{5}\\x = \frac{(27)(5)}{3}\\x = 45$

The couple rested for 45 minutes in 5 hours.

4 0

4 years ago

39-50 find the limit.<br> 41. <img src="https://tex.z-dn.net/?f=%5Clim%20_%7Bt%20%5Crightarrow%200%7D%20%5Cfrac%7B%5Ctan%206%20t

Katyanochek1 [597]

Write tan in terms of sin and cos.

$\displaystyle \lim_{t\to0}\frac{\tan(6t)}{\sin(2t)} = \lim_{t\to0}\frac{\sin(6t)}{\sin(2t)\cos(6t)}$

Recall that

$\displaystyle \lim_{x\to0}\frac{\sin(x)}x = 1$

Rewrite and expand the given limand as the product

$\displaystyle \lim_{t\to0}\frac{\sin(6t)}{\sin(2t)\cos(6t)} = \lim_{t\to0} \frac{\sin(6t)}{6t} \times \frac{2t}{\sin(2t)} \times \frac{6t}{2t\cos(6t)} \\\\ = \left(\lim_{t\to0} \frac{\sin(6t)}{6t}\right) \times \left(\lim_{t\to0}\frac{2t}{\sin(2t)}\right) \times \left(\lim_{t\to0}\frac{3}{\cos(6t)}\right)$

Then using the known limit above, it follows that

$\displaystyle \left(\lim_{t\to0} \frac{\sin(6t)}{6t}\right) \times \left(\lim_{t\to0}\frac{2t}{\sin(2t)}\right) \times \left(\lim_{t\to0}\frac{3}{\cos(6t)}\right) = 1 \times 1 \times \frac3{\cos(0)} = \boxed{3}$

4 0

2 years ago