The x =0 and y = 1 are coordinates of point E, which partitions the directed line segment from A to B into a ratio of 1:2.
<h2>We have to determine</h2>
What are the x- and y- coordinates of point E, which partitions the directed line segment from A to B into a ratio of 1:2?
<h3>According to the question</h3>
A line segment at points A(2, -3) and B (-4, 9).
The x- and y- coordinates of point E, which partitions the directed line segment from A to B into a ratio of 1:2 is given by;
![\rm x=\dfrac{m}{(m+n)} [x_2- x_1]+ x_1 \\ \\ y=\dfrac{m}{(m+n)} [y_2- y_1]+ y_1 \\ \\](https://tex.z-dn.net/?f=%5Crm%20x%3D%5Cdfrac%7Bm%7D%7B%28m%2Bn%29%7D%20%5Bx_2-%20x_1%5D%2B%20x_1%20%5C%5C%0A%5C%5C%0A%20y%3D%5Cdfrac%7Bm%7D%7B%28m%2Bn%29%7D%20%5By_2-%20y_1%5D%2B%20y_1%20%5C%5C%0A%5C%5C)
Where 
Substitute all the values in the formula;
![\rm x=\dfrac{m}{(m+n)} [x_2- x_1]+ x_1 \\\\](https://tex.z-dn.net/?f=%5Crm%20x%3D%5Cdfrac%7Bm%7D%7B%28m%2Bn%29%7D%20%5Bx_2-%20x_1%5D%2B%20x_1%20%5C%5C%5C%5C%20)
![\rm x=\dfrac{1}{(1+2)} [-4-(2)]+ (2)\\\\ x = \dfrac{1}{3} \times (-6) +2 \\ \\ x = -2+2\\ \\ x=0](https://tex.z-dn.net/?f=%5Crm%20x%3D%5Cdfrac%7B1%7D%7B%281%2B2%29%7D%20%5B-4-%282%29%5D%2B%20%282%29%5C%5C%5C%5C%20x%20%3D%20%5Cdfrac%7B1%7D%7B3%7D%20%5Ctimes%20%28-6%29%20%2B2%20%5C%5C%0A%5C%5C%0Ax%20%3D%20-2%2B2%5C%5C%0A%5C%5C%0Ax%3D0)
![\rm y=\dfrac{m}{(m+n)} [y_2- y_1]+ y_1 \\\\ y=\dfrac{1}{(1+2)} [9-(-3)]+ (-3)\\\\ y = \dfrac{1}{3} \times (12) -3\\ \\ y = 4-3\\ \\ y =1](https://tex.z-dn.net/?f=%5Crm%20y%3D%5Cdfrac%7Bm%7D%7B%28m%2Bn%29%7D%20%5By_2-%20y_1%5D%2B%20y_1%20%5C%5C%5C%5C%20y%3D%5Cdfrac%7B1%7D%7B%281%2B2%29%7D%20%5B9-%28-3%29%5D%2B%20%28-3%29%5C%5C%5C%5C%0Ay%20%3D%20%5Cdfrac%7B1%7D%7B3%7D%20%5Ctimes%20%2812%29%20-3%5C%5C%0A%5C%5C%0Ay%20%3D%204-3%5C%5C%0A%5C%5C%0Ay%20%3D1)
Hence, the x =0 and y = 1 are coordinates of point E, which partitions the directed line segment from A to B into a ratio of 1:2.
To know more about Coordinates click the link given below.
brainly.com/question/13847533
Answer:
C
Step-by-step explanation:
Since 3 does not equal 6, therfore the answer is no solution.
Answer:
If you multiply 256 by 10 powered by k, then the number of zeros in the product is k
Step-by-step explanation:
Let x be any integer, if you multiply x by 10 you will have to add one zero at the right of x. If you multiply by 10 again, you will have to add a second zero at the right, thus if you multiply by 100, you will have to add 2 zeros. If you multiply by 1000 = 10*10*10 = 10³ you will have to add 3 zeros and so on.
Therefore, if you multiply 256 by 10^k, then you will have to add k zeros to 256, and as a consequence, the amount of zeros in the product is equal to the power of 10 we are multiplying.
I'm sorry I'm not home so I can't tell you the answer to this but what I can tell you is put together the xy and then put together the -13-20. Hope this helps.
