3 years ago

How do you solve 1/4(b-8)^2=7?

Mathematics

1 answer:

d1i1m1o1n [39]3 years ago

4 0

$1/4 (b - 8)^2 = 7\\(b - 8)^2 = 7 \times 4 = 28\\b - 8 = \sqrt{28}=2\sqrt{7}\\b = 8+2\sqrt{7}$

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