Answer:
If two sound waves differ in intensity, the wave that is more intense sounds_________.
Answer: Louder
Answer:
Explanation:
A ) Distance between two adjacent anti-node will be equal to distance between two adjacent nodes . So the required distance is 15 cm .
B ) wave-length, amplitude, and speed of the two traveling waves that form this pattern are as follows
wave length = same as wave length of wave pattern formed. so it is 30 cm
amplitude = 1/2 the amplitude of wave pattern formed so it is .850 / 2 = .425 cm
Speed = frequency x wavelength ( frequency = 1 / time period )
= 1 / .075) x 30 cm
400 cm / m
C ) maximum speed
= ω A
= (2π / T) x A
= 2 X 3.14 x .85 / .075 cm / s
= 71.17 cm / s
minimum speed is zero.
D ) The shortest distance along the string between a node and an antinode
= Wavelength / 4
= 30 / 4
= 7.5 cm
Answer:
the speed that have 0.0100 kilogram bullet with the similar momentum magnitude is 360 m/s
Explanation:
The computation of the speed that have 0.0100 kilogram bullet with the similar momentum magnitude is as follows:
The ball momentum is
As there is a similar momentum
So,
Hence, the speed that have 0.0100 kilogram bullet with the similar momentum magnitude is 360 m/s
Answer:
Final angular velocity is 35rpm
Explanation:
Angular velocity is given by the equation:
I1w1i + I2w2i = I1w1f -I2w2f
But the two disks are identical, so Ii =I2
wf can be calculated using
wf = w1i - w2i/2
Given: w1i =50rpm w2i= 30rpm
wf= (50 + 20) / 2
wf= 70/2 = 35rpm
<span>Time needed for drive a distance 100 km at 100 km/h:
t1 =100/100
= 1 h
Time needed for drive a distance 40 km at 45 km/h:
t2 =40/45
=0.8 h
t3 =3h 15m - 1 h- 0.8 h
=1.45 h
Distance to town equals:
s3 =270-100-40
=130 km
Least speed needed to arrive in time for the interview:
v3 =130 km/1.45 h
=89.65 km/h
The answer is 89.65 km/h</span>
