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andrew-mc [135]
3 years ago
12

You are to drive to an interview in another town, at a distance of 270 km on an expressway. the interview is at 11:15

Physics
1 answer:
Crazy boy [7]3 years ago
6 0
<span>Time needed for drive a distance 100 km at 100 km/h: t1 =100/100 = 1 h Time needed for drive a distance 40 km at 45 km/h: t2 =40/45 =0.8 h t3 =3h 15m - 1 h- 0.8 h =1.45 h Distance to town equals: s3 =270-100-40 =130 km Least speed needed to arrive in time for the interview: v3 =130 km/1.45 h =89.65 km/h The answer is 89.65 km/h</span>
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A pitcher throws a baseball that reaches the catcher in 0.75 s. The ball curves because it is spinning at an average angular vel
7nadin3 [17]

The change in angular displacement as a function of time is the definition given for angular velocity, this is mathematically described as

\omega = \frac{\theta}{t}

Here,

\theta = Angular displacement

t = time

The angular velocity is given as

\omega = 230rev/min

PART A) The angular velocity in SI Units will be,

\omega = 230rev/min (\frac{1min}{60s})(\frac{2\pi rad}{1rev})

\omega = \frac{23}{3}\pi rad/s \approx 24.08rad/s

PART B) From our first equation we can rearrange to find the angular displacement then

\theta = \omega t

Replacing,

\theta = (24.08)(0.75)

\theta = 18.06 rad

4 0
3 years ago
A flywheel in a motor is spinning at 590 rpm when a power failure suddenly occurs. The flywheel has mass 40.0 kg and diameter 75
Gnom [1K]

Answer:

Explanation:

Hello,

Let's get the data for this question before proceeding to solve the problems.

Mass of flywheel = 40kg

Speed of flywheel = 590rpm

Diameter = 75cm , radius = diameter/ 2 = 75 / 2 = 37.5cm.

Time = 30s = 0.5 min

During the power off, the flywheel made 230 complete revolutions.

∇θ = [(ω₂ + ω₁) / 2] × t

∇θ = [(590 + ω₂) / 2] × 0.5

But ∇θ = 230 revolutions

∇θ/t = (530 + ω₂) / 2

230 / 0.5 = (530 + ω₂) / 2

Solve for ω₂

460 = 295 + 0.5ω₂

ω₂ = 330rpm

a)

ω₂ = ω₁ + αt

but α = ?

α = (ω₂ - ω₁) / t

α = (330 - 590) / 0.5

α = -260 / 0.5

α = -520rev/min

b)

ω₂ = ω₁ + αt

0 = 590 +(-520)t

520t = 590

solve for t

t = 590 / 520

t = 1.13min

60 seconds = 1min

X seconds = 1.13min

x = (60 × 1.13) / 1

x = 68seconds

∇θ = [(ω₂ + ω₁) / 2] × t

∇θ = [(590 + 0) / 2] × 1.13

∇θ = 333.35 rev/min

8 0
3 years ago
The ocean floor is covered with thick layers of _____,______, and ________.
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7 0
3 years ago
Read 2 more answers
An object that travels around another object in space is called a(n)
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Satellite. think of the moon.

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3 0
3 years ago
Read 2 more answers
In Milgram's experiment:
SpyIntel [72]

Answer:

B. The "Learner" was working with Milgram.

Explanation:

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