3 years ago

What mass is 2.4E25 molecules of NaHCO3?

Chemistry

1 answer:

Zigmanuir [339]3 years ago

7 0

Answer:

Explanation:

Mole = no. Molecules/6.02×10^23

Mole = (2.4×10^25)/(6.02×10^23)

Mole = 39.87mole

Molar mass of NaHCO3 is

= 23 + 1 + 12 + 3(16)

= 84g/mol

Mole = mass/molar mass

Mass = Mole × molar mass

Mass = 39.87 × 84

Mass= 3348.84g

You might be interested in

45.8 g of NaCl is dissolved in 500. mL of a water (d = 1.00 g/mL) and is placed in the freezer at -1 °C overnight. Which stateme

mel-nik [20]

Answer:

i honestly don't know.

Explanation:

4 0

3 years ago

Based on the experiment, do you think birds can just wash off the oil with water? Explain your answer.

ankoles [38]

Answer:

Explanation:

as it would stay sticked on them forerver amd a time of 2 months it will kill them

7 0

2 years ago

Read 2 more answers

5. The mass of cobalt-60 in a sample is found to have decreased from 0.800g to 0.200g in a

Ludmilka [50]

Answer:

5.25yr

Explanation:

I think so

6 0

2 years ago

Please help mee!!!!

GREYUIT [131]

The meaning of observations to see small touch

6 0

2 years ago

What is the empirical formula for a compound if 300.00 g of it is known to contain 82.46224 g of molybdenum, 45.741 g of chlorin

Marysya12 [62]

Answer:

MoClBr₂

Explanation:

First we calculate the mass of bromine in the compound:

300.00 g - (82.46224 g + 45.741 g) = 171.79676 g

Then we calculate the number of moles of each element, using their respective molar masses:

82.46224 g Mo ÷ 95.95 g/mol = 0.9594 mol Mo

45.741 g Cl ÷ 35.45 g/mol = 1.290 mol Cl

171.79676 g Br ÷79.9 g/mol = 2.150 mol Br

Now we divide those numbers of moles by the lowest number among them:

0.9594 mol Mo / 0.9594 = 1

1.290 mol Cl / 0.9594 = 1.34 ≅ 1

2.150 mol Br / 0.9594 = 2.24 ≅ 2

Meaning the empirical formula is MoClBr₂.

8 0

2 years ago