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3 years ago

What mass is 2.4E25 molecules of NaHCO3?

Chemistry

1 answer:

Zigmanuir [339]3 years ago

7 0

Answer:

Explanation:

Mole = no. Molecules/6.02×10^23

Mole = (2.4×10^25)/(6.02×10^23)

Mole = 39.87mole

Molar mass of NaHCO3 is

= 23 + 1 + 12 + 3(16)

= 84g/mol

Mole = mass/molar mass

Mass = Mole × molar mass

Mass = 39.87 × 84

Mass= 3348.84g

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4+4=?

lesya692 [45]

Answer:

Explanation:

3 0

3 years ago

Read 2 more answers

When heat is applied to 80 grams of CaCO3, it yields 39 grams of B. Determine the percentage of the yield.

EleoNora [17]

The question is incomplete, the complete question is:

When heat is applied to 80 grams of CaCO3, it yields 39 grams of CaO Determine the percentage of the yield.

CaCO3→CaO + CO2

Answer: The % yield of the product is 87.05 %

Explanation:

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

We are given:

Given mass of $CaCO_3$ = 80 g

Molar mass of $CaCO_3$ = 100 g/mol

Putting values in equation 1, we get:

$\text{Moles of }CaCO_3=\frac{80g}{100g/mol}=0.8mol$

For the given chemical reaction:

$CaCO_3\rightarrow CaO+CO_2$

By stoichiometry of the reaction:

If 1 mole of $CaCO_3$ produces 1 mole of CaO

So, 0.8 moles of $CaCO_3$ will produce = $\frac{1}{1}\times 0.8=0.8mol$ of CaO

We know, molar mass of $CaO$ = 56 g/mol

Putting values in above equation, we get:

$\text{Mass of CaO}=(0.8mol\times 56g/mol)=44.8g$

The percent yield of a reaction is calculated by using an equation:

$\% \text{yield}=\frac{\text{Actual value}}{\text{Theoretical value}}\times 100$ ......(2)

Given values:

Actual value of the product = 39 g

Theoretical value of the product = 44.8 g

Plugging values in equation 2:

$\% \text{yield}=\frac{39 g}{44.8g}\times 100\\\\\% \text{yield}=87.05\%$

Hence, the % yield of the product is 87.05 %

6 0

2 years ago

Need a bit of help with this. Fill in the coefficients, explain your answer.

sp2606 [1]

Answer:

4Fe + 3O₂ → 2Fe₂O₃

General Formulas and Concepts:

Chemistry - Reactions

Balancing Reactions

Explanation:

Step 1: Define

RxN: Fe + O₂ → Fe₂O₃

Step 2: Balance

We need to balance both Fe and O.

LCM of 2 and 3 is 6:

Fe + 3O₂ → 2Fe₂O₃

We now need the same amount of Fe on both sides:

4Fe + 3O₂ → 2Fe₂O₃

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3 years ago

When heating a chemical solution over an open flame in a test tube you should - A. keep a cork in the test tube so the solution

Alla [95]

Hello.

The answer is: A. keep a cork in the test tube so the solution cannot spill out

B and C both could be very deadly and it shouldnt be D because if u have an open flame you shouldnt open it even if its not towards anyone.

have a nice day

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3 years ago

Which atom has the largest atomic radius

Greeley [361]

francium , in the Periodic table the atomic radius increases from top to bottom in a group, and decreases from left to right across a period. making helium is the smallest element, and francium the largest.

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3 years ago