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fiasKO [112]
4 years ago
7

What are mole ratios used for?

Chemistry
1 answer:
zhenek [66]4 years ago
4 0
<span>Mole ratios are used as conversion factors between products and reactants in many chemistry problems.</span>
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A(n) __________ is formed when one atom loses an electron and another atom accepts that electron.
Roman55 [17]
The answer is a cation
8 0
3 years ago
To neutralize 1.65g LiOH, how much .150 M HCl would be needed
Vinvika [58]
The molecular weight of LiOH would be 23.95 g/mol, so the amount of LiOH in mol would be: 1.64g/(<span>23.95 g/mol)= 0.069 mol

The reaction of LiOH with HCl would be:
</span><span>HCl + LiOH = H2O + LiCl
The coefficient of LiOH:HCL is 1:1 so you need the same amount of HCl to neutralize LiOH.

HCl= LiOH
volume* 0.15M= </span>0.069 mol
volume= 0.069 mol/ (0.15 mol/ 1000ml)
volume= 459.29 ml
4 0
3 years ago
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Nookie1986 [14]

Answer:

B

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RSB [31]

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5 0
3 years ago
At 2000 ∘c the equilibrium constant for the reaction 2no(g)⇌n2(g)+o2(g) is kc=2.4×103. part a if the initial concentration of no
luda_lava [24]

Answer:

[NO] = 1.72 x 10⁻³ M.  

Explanation:

  • For the reaction:

<em>2NO(g) ⇌ N₂(g)+O₂(g),</em>

Kc =  [N₂][O₂] / [NO]².

  • At initial time: [NO] = 0.171 M,  [N₂] = [O₂] = 0.0 M.
  • At equilibrium: [NO] = 0.171 M - 2x ,  [N₂] = [O₂] = x M.

∵ Kc =  [N₂][O₂] / [NO]².

∴ 2400 = x² / (0.171 - 2x)² .

<u><em>Taking the aquare root for both sides:</em></u>

√(2400) = x / (0.171 - 2x)  

48.99 = x / (0.171 - 2x)  

48.99 (0.171 - 2x) = x  

8.377 - 97.98 x = x

8.377 = 98.98 x.

∴ x = 8.464 x 10⁻².

<em>∴ [NO] = 0.171 - 2(8.464 x 10⁻²) = 1.72 x 10⁻³ M.  </em>

<em>∴ [N₂] = [O₂] = x = 8.464 x 10⁻² M.</em>

3 0
3 years ago
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