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Eddi Din [679]
2 years ago
9

A Calorie unit used in food is equal to the amount of energy necessary to raise the temperature of 1 kilogram of water ________

degrees) Celsius.
Chemistry
1 answer:
Kitty [74]2 years ago
7 0

A Calorie unit used in food is equal to the amount of energy necessary to raise the temperature of 1 kilogram of water by <u>1</u> degrees Celsius.

<h3>What is One Calorie ?</h3>

The amount of heat energy required to raise the temperature by 1 gram of water through 1°C is known as One Calorie.

1 Calorie = 4.18 J

Thus from the above conclusion we can say that A Calorie unit used in food is equal to the amount of energy necessary to raise the temperature of 1 kilogram of water by <u>1</u> degrees Celsius.

Learn more about the One calorie here: brainly.com/question/1061571

#SPJ4

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Blank 1: nothing (to keep 2 total nitrogen)
blank 2: 3 (to make 6 total hydrogen)
blank 3: 2 (to make 2 total nitrogen and 6 total hydrogen)

hope this helps!! :)
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3 years ago
What is the formula for the ionic compound formed by magnesium and iodine?
MrMuchimi
The compound that is formed is: MgI2
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What is the mole fraction of O2O2 in a mixture of 15.1 gg of O2O2, 8.19 gg of N2N2, and 2.46 gg of H2H2
SVETLANKA909090 [29]

Answer:

Mole fraction O₂=  0.43

Explanation:

Mole fraction is the moles of gas/ total moles.

Let's determine the moles of each:

Moles O₂ → 15.1 g / 16 g/mol = 0.94

Moles N₂  →  8.19 g / 14 g/mol = 0.013

Moles H₂  → 2.46 / 2 g/mol = 1.23

Total moles = 2.183

Mole fraction O₂= 0.94 / 2.183 → 0.43

3 0
4 years ago
4. A student purified a 500-mg sample of phthalic acid by recrystallization from water. The published solubility of phthalic aci
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Answer:

2.77 mL of boiling water is the minimum amount which will dissolve 500 mg of phthalic acid.

Explanation:

We know from the problem that 18 g of phthalic acid are dissolved in 100 mL of water at 99 °C.

Now we devise the following reasoning:

If          18 g of phthalic acid are dissolved in 100 mL of water at 99 °C

Then   0.5 g of phthalic acid are dissolved in X mL of water at 99 °C

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7 0
3 years ago
Question 2: Heat (5 points)
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Answer:

(i) specific heat

(ii) latent heat of vaporization

(iii) latent heat of fusion

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i. Q = mcΔT; identify c.

Here, Q is heat, m is the mass, c is the specific heat and ΔT is the change in temperature.

The amount of heat required to raise the temperature of substance of mass 1 kg by 1 degree C is known as the specific heat.  

ii. Q = mLvapor; identify Lvapor

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The amount of heat required to convert the 1 kg liquid into 1 kg vapor at constant temperature.  

iii. Q = mLfusion; identify Lfusion

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Here, Q is the heat, m is the mass and L is the latent heat of vaporization.

The amount of heat required to convert the 1 kg solid  into 1 kg liquid at constant temperature.  

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