<span>3Mg(NO3)2 + 2K3PO4 ---> Mg3(PO4)2 + 6KNO3
n(</span>K3PO4):n(KNO3)=2:6=1:3
n(K3PO4):n(KNO3)=1:3
Answer:
Dissociation factor = 1.8
Explanation:
Data provided in the question:
Molecular weight of the Procaine hydrochloride = 273
Number of ions contained, n = 2
Fraction Dissociating, α = 80% = 0.8
Now,
the dissociation factor 'i' is given as:
i = 1 + α × ( n - 1 )
on substituting the respective values, we get
i = 1 + 0.8 × ( 2 - 1 )
or
i = 1 + ( 0.8 × 1 )
or
i = 1.8
Answer:
This is the typical route of alcohol metabolism, where in the liver it is first transformed to acetaldehyde and then to acetate.
Explanation:
Ethanol is not digested but absorbed and follows its metabolic pathway in the liver, producing in the first instance acetaldehyde, which is the main substance that causes the hangover and then this compound is transformed into the final product, which is acetate Later acetate is metabolized to Acetyl-CoA. The enzyme responsible for the metabolism of ethanol is alcohol dehydrogenase in the liver, and for the cytochrome P-450 dependent system and for catalase in the liver.
Answer:
Strong acids are assumed 100% dissociated in water- True
As a solution becomes more basic, the pOH of the solution increases- false
The conjugate base of a weak acid is a strong base- true
The Ka equilibrium constant always refers to the reaction of an acid with water to produce the conjugate base of the acid and the hydronium ion- True
As the Kb value for a base increases, base strength increases- true
The weaker the acid, the stronger the conjugate base- true
Explanation:
An acid is regarded as a strong acid if it attains 100% or complete dissociation in water.
The pOH decreases as a solution becomes more basic (as OH^- concentration increases).
Ka refers to the dissociation of an acid HA into H3O^+ and A^-.
The greater the base dissociation constant, the greater the base strength.
The weaker an acid is, the stronger , its conjugate base will be.
Concentration is found by dividing the mass of solute by the volume of the solution. C = 4.2g/0.25 L. C= 16.8 g/L
