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Natalija [7]
3 years ago
12

The original list from the Stockholm Convention on Persistent Organic Pollutants (POPs) of 12 hazardous chemicals, called the __

__________________, which includes DDT and eight other chlorine-containing persistent pesticides, PCBs, dioxins, and furans.
Chemistry
1 answer:
o-na [289]3 years ago
5 0

Answer:

The dirty dozen.

Explanation:

This is mainly seen in the control of hazardous waste and its regulations through treaty in the control of persistent organic pollutant(POPs). This regulation is seen to occur in 12 widely used persistent organic pollutants; these are seen to have the ability to absorb and store tissues that make them fatty especially in humans and also animals found in the higher trophic levels or in the food web. That being said, it can be noted that the dirty dozen can move or even attain hundreds, or thousands of levels towards the environ and also in other cases, transporting them through air or water as the case may be.

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When selling on the street, dealers may not know the purity of the ketamine they have, and thus users do not know exactly how mu
fiasKO [112]

Answer:

a. 6.15 mL b. 30.73 mL

Explanation:

a. What volume of this ketamine solution would the 65.0 kg user have to inject to experience a high at 0.400 mg/kg?

Since we have 0.250 g of ketamine in 1/4 cup of water and 1 cup of water equals 236.5 mL, we need to find the concentration of ketamine we have.

So concentration of ketamine C = mass of ketamine, m/volume of water, V

m = 0.250 g and V = 1/4 cup = 1/4 × 236.5 mL = 59.125 mL

So, C = m/V = 0.250 g/59.125 mL = 0.00423 g/mL = 4.23 mg/mL

Since the user has a mass of 65 kg and requires a high at 0.400 mg/kg, the mass of ketamine for this high is M = 65 kg × 0.400 mg/kg = 26 mg

Since mass, M = concentration ,C × volume, V

M = CV

V = M/C

The volume of ketamine required for the 0.400 mg/kg high is

V = 26 mg/4.23 mg/mL

V = 6.15 mL

b. What volume of this ketamine solution would the user have to inject to become unconscious at 2.00 mg/kg?

Since the concentration of ketamine is C = 4.23 mg/mL, and Since the user has a mass of 65 kg and requires an injection of 2.00 mg/kg to be unconscious, the mass of ketamine required to be unconscious is M' = 65 kg × 2.00 mg/kg = 130 mg

Since mass, M' = concentration ,C × volume, V

M' = CV

V = M/C

The volume of ketamine required for the 2.00 mg/kg unconscious injection is

V = 130 mg/4.23 mg/mL

V = 30.73 mL

5 0
2 years ago
According to newtons 3rd law, an action creates​
Otrada [13]

Answer:

An equal reaction

Hope this Helps :)

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3 years ago
What descriptive term is applied to the type of diene represented by 2,4-hexadiene?.
Varvara68 [4.7K]

The descriptive term applied to the type of diene represented by 2,4-hexadiene is conjugated diene.

Dienes are compounds which contains two double bonds. These dienes can be non conjugated or conjugated.

Conjugated diene are those compound which have two double bonds  joined by a single σ bond. Conjugated dienes can also be called 1,3-diene. To know if diene is conjugated or non conjugated, sp³ hybridization is to b checked and the number of double bonds and single sigma bond is checked.

Conjugated dienes are found in many different molecules. 2,4-hexadiene is a conjugated diene with two carbon-carbon double bonds that are separated by one sigma bond.

The stabilization of dienes by conjugation is better than the aromatic stabilization. Conjugated dienes are more stable than non conjugated or cumulative diene because it has higher electron density of molecules delocalized.

To learn more about conjugated dienes,

brainly.com/question/24261651

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Answer:

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