Divide using long division. (9p2 + 8p3 + 12) ÷ (p + 1)

Mathematics

2 answers:

DaniilM [7]3 years ago

7 0

Answer:

8p^2+p-1 with a remainder of 13

Step-by-step explanation:

p+1 divided by 8p^3+9p^2+0p+12

kodGreya [7K]3 years ago

3 0

Answer:

8p∧2 ± p - 1 ± 13/p ± 1

Step-by-step explanation:

Divide (9p2 + 8p3 + 12) ÷ (p + 1) and it equals 8p∧2 ± p - 1 ± 13/p ± 1

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Given that m=r-s/2nr

r-ruslan [8.4K]

Step-by-step explanation:

$m = \frac{r - s}{2nr}$

m(2nr) = r-s

2×n×r×m = r-s

move the r on the right side to the left side

2nrm - r = -s

r ( 2nm - 1 ) = -s

$r \: = \frac{ - s}{(2nm - 1)}$

4 0

3 years ago

Read 2 more answers

Please help soon!

Jlenok [28]

Answer:

a) Translate the graph of f(x) down 3 units.

b) (8,-1) is a point on the graph of g(x)

Step-by-step explanation:

The transformations that subtract a constant number of units from the functional expression f(x) are transformations that lower the graph of the function in those many units,

Therefore they correspond to a translation of the original graph down the number of units involved.

In this case, the number of units involved is "3" (due to the "-3" added to the expression for f(x). So he correct answer for the first part is: Translate the graph of f(x) down 3 units.

For the second part, one has to try each of the coordinate pairs given in the new function g(x) to see which one results in a true statement:

1) Testing (-8,-1) by checking if replacing x with the value "-8" renders "-1" for the y-value: $g(x)=\sqrt[3]{x} -3\\g(-8)=\sqrt[3]{-8} -3\\g(-8)=-2-3\\g(-8)=-5$

so this is NOT a point on the graph of g(x).

2) Testing (-1,-2) by checking if replacing x with the value "-1" renders "-2" for the y-value: $g(x)=\sqrt[3]{x} -3\\g(-1)=\sqrt[3]{-1} -3\\g(-1)=-1-3\\g(-1)=-4$

so this is NOT a point on the graph of g(x).

3) Testing (2,-1) by checking if replacing x with the value "2" renders "-1" for the y-value: $g(x)=\sqrt[3]{x} -3\\g(2)=\sqrt[3]{2} -3\\$

the cubic root of 2 is not a rational number, because 2 is not a perfect cube, so the expression cannot be reduced, so this is NOT a point on the graph of g(x).

4) Testing (8,-1) by checking if replacing x with the value "8" renders "-1" for the y-value: $g(x)=\sqrt[3]{x} -3\\g(8)=\sqrt[3]{8} -3\\g(8)=2-3\\g(8)=-1$