Answer:
It's not possible to answer the question with the information provided, you will need to post the ratios in the problem.
Step-by-step explanation:
Given :
An equation, 2cos ß sin ß = cos ß .
To Find :
The value for above equation in (0, 2π ] .
Solution :
Now, 2cos ß sin ß = cos ß
2 sin ß = 1
sin ß = 1/2
We know, sin ß = sin (π/6) or sin ß = sin (5π/6) in ( 0, 2π ] .
Therefore,

Hence, this is the required solution.
Answer: 1) x> -21
2) x is less than or equal to -21
3) x is less than or equal to 16
4) x less than or equal to 3/4
The ratio of the geometric sequence 40
is 2.
Given that geometric sequence is 40*
and we have to find the common ratio of all the terms.
Geometric sequence is a sequence in which all the terms have a common ratio.
Nth termof a GP is a
in which a is first term and r is common ratio.
Geometric sequence=40*
We have to first find the first term, second term and third term of a geometric progression.
First term=40*
=40*
=40*1
=40
Second term=40*
=40*
=40*2
=80
Third term=40*
=40*
=40*4
=160
Ratio of first two terms=80/40=2
Ratio of next two terms=160/80=2
Hence the common ratio of geometric sequence is 2.
Learn more about geometric progression at brainly.com/question/12006112
#SPJ1
<span> -14x + 11y = 23
+2(7x - 3y = 37)
----------------------
0 + 5y = 97
y = 97/5
y = 19.4
7x - 3(19.4) = 37
7x - 58.2 = 37
7x = 37 + 58.2
7x = 95.2
x = 95.2/7
x = 13.6
Check
-14(13.6) + 11(19.4) = 23
-190.4 + 213.4 = 23
</span>