Answer:
0.683 moles of the gas are required
Explanation:
Avogadro's law relates the moles of a gas with its volume. The volume of a gas is directely proportional to its moles when temperature and pressure of the gas remains constant. The law is:
V₁n₂ = V₂n₁
<em>Where V is volume and n are moles of 1, initial state and 2, final state of the gas.</em>
<em />
Computing the values of the problem:
1.50Ln₂ = 5L*0.205mol
n₂ = 0.683 moles of the gas are required
<em />
Newton's third law of motion states that for every action force, there is an equal and opposite reaction force so that means that the wall is pushing you with the same amount of force that you put on it.
Answer:

Explanation:
We must use the Nernst equation

Step 1. Calculate E°
SO₄²⁻(aq) + 4H⁺(aq) + 2e⁻ ⇌ SO₂(g) + 2H₂O(ℓ)
<u>2Br⁻⇌ Br₂(aq) + 2e⁻ </u>
SO₄²⁻(aq) + 4H⁺(aq) + 2Br⁻(aq) ⇌ Br₂(aq) + SO₂(g) + 2H₂O(ℓ)
E° = 0.17 - 1.0873 = -0.92 V
Step 2. Calculate Q
E = 0 V
E° = -0.92 V
R = 8.314 J·K⁻¹mol⁻¹
T = 66 °C
n = 2
F = 96 485 C/mol
Calculations:
T = 66.0 + 273.15 = 339.15 K

<h3>
Answer:</h3>
3.33 mol H₂O
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
60.0 g H₂O (Water)
<u>Step 2: Identify Conversions</u>
Molar Mass of H - 1.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol
<u>Step 3: Convert</u>
- Set up:

- Multiply:

<u>Step 4: Convert</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
3.32963 mol H₂O ≈ 3.33 mol H₂O