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Mashcka [7]
3 years ago
15

Jesse notices that his gas mileage jumps from 20 to 40 per gallon when he uses his cruise control. One likely explanation for th

is is:
a. jesse's car is powered by a biofuel that is not needed while cruising
b. jesse's car is compressing and expanding efficiently
c. jesse's car has an efficient air-to-fuel ratio
d. jesse's car is a hybrid that shuts off extra pistons when it is not accelerating
Chemistry
1 answer:
stich3 [128]3 years ago
6 0
<h3><u>Answer;</u></h3>

D. jesse's car is a hybrid that shuts off extra pistons when it is not accelerating

<h3><u>Explanation;</u></h3>
  • When cruising, hybrid cars are able to employ electrical energy to drive the car.
  • Moreover, even if a vehicle is not a hybrid, a greater amount of fuel is consumed when one accelerates because the vehicle has to generate a force larger than the force of air resistance in order for it to accelerate.
  • This increased demand of force reduces the vehicle's fuel economy.
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When this happens the inward force of gravity is exactly balanced with the outward force created by _______ and _____________.
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3 years ago
A binding protein binds to a ligand l with a kd of 400 nm. what is the concentration of ligand when y is (a) 0.25, (b) 0.6, (c)
lilavasa [31]

Hey there!:

The fractional saturation y is defined as :

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3 0
4 years ago
The​ half-life of​ plutonium-241 is approximately 13 years. a. How much of a sample weighing 2 g will remain after 70 ​years? b.
Studentka2010 [4]

Answer: A) 0.0480 grams and B) 56.16 years.

Explanation: Half live is the time in which the amount of radioactive substance remains halve of its initial amount.

The formula we use for solving this type of problem is:

\frac{N}{N_0}=(\frac{1}{2})^n

where, N_0 is the initial amount and N is the remaining amount of radioactive substance and n is the number of half lives.

n=T/t_1_/_2

where, T is the time and t_1_/_2 is half life.

A) from given data, N_0 = 2 g

T = 70 years

t_1_/_2 = 13 years

N= ?

n=\frac{70years}{13years}

n = 5.38

\frac{N}{2g}=(\frac{1}{2})^5^.^3^8

\frac{N}{2g}=0.0240

N = 0.0480 g

So, 0.0480 grams of the substance will be remaining after 70 years.

B) N_0 = 2 g

N = 0.1 g

T = ?

Let's first calculate the value of n for this.

\frac{0.1}{2}=(\frac{1}{2})^n

0.05=0.5^n

Taking log to both sides:

log0.05=nlog0.5

-1.301=n(-0.3010)

n=\frac{1.3010}{0.3010}

n = 4.32

Half life is 13 years, so we can calculate the time as:

n=T/t_1_/_2

T=n*t_1_/_2

T=4.32*13years

T = 56.16 years

So, it will take 56.16 years for the radioactive substance to decay from 2 g to 0.1 g.

8 0
4 years ago
Read 2 more answers
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