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Mashcka [7]
3 years ago
15

Jesse notices that his gas mileage jumps from 20 to 40 per gallon when he uses his cruise control. One likely explanation for th

is is:
a. jesse's car is powered by a biofuel that is not needed while cruising
b. jesse's car is compressing and expanding efficiently
c. jesse's car has an efficient air-to-fuel ratio
d. jesse's car is a hybrid that shuts off extra pistons when it is not accelerating
Chemistry
1 answer:
stich3 [128]3 years ago
6 0
<h3><u>Answer;</u></h3>

D. jesse's car is a hybrid that shuts off extra pistons when it is not accelerating

<h3><u>Explanation;</u></h3>
  • When cruising, hybrid cars are able to employ electrical energy to drive the car.
  • Moreover, even if a vehicle is not a hybrid, a greater amount of fuel is consumed when one accelerates because the vehicle has to generate a force larger than the force of air resistance in order for it to accelerate.
  • This increased demand of force reduces the vehicle's fuel economy.
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which statement regarding the relative energies of monochromatic light with with λ = 800 nm andmonochromatic light with λ = 400
olga2289 [7]

Answer:

The correct answer is option A.

Explanation:

Energy of the photon of an electromagnetic radiation is give by Planck's equation:

E=\frac{hc}{\lambda }

Where:

h = Planck's constant

c = speed of light

\lambda = Wavelength of the photon's radiation

Energy of photon of 800 nm monochromatic light

\lambda = 800 nm=400\times 10^{-9} m

E=\frac{hc}{800 \times 10^{-9} m}

Energy per mole of photons:

E\times N_A=\frac{hc}{800 \times 10^{-9} m}\times 6.022\times 10^{23} mol^{-1}..[1]

Energy of photon of 400 nm monochromatic light

\lambda '= 400 nm=400\times 10^{-9} m

Energy per mole of photons:

E'\times N_A=\frac{hc}{400 \times 10^{-9} m}\times 6.022\times 10^{23} mol^{-1}..[2]

[1] ÷ [2]

\frac{E\times N_A}{E'\times N_A}=\frac{\frac{hc\trimes 6.022\times 10^{23} mol^{-1}}{800 \times 10^{-9} m}}{\frac{hc\times 6.022\times 10^{23} mol^{-1}}{400 \times 10^{-9} m}}

\frac{E}{E'}=\frac{1}{2}

E=\frac{1}{2}\times E'

8 0
3 years ago
Read 2 more answers
How many nitrogen atoms are present in 0.150 mol of zn(no3)2?
gregori [183]
First calculate number of Nitrogen atoms contained by 1 mole of Zn(NO₃)₂,

As one formula unit of Zn(NO₃)₂ contains 2 Nitrogen atoms, then one mole of Zn(NO₃)₂ will contain,

                           =  2 × 6.022 × 10²³

                           =  1.20 × 10²⁴ Atoms of Nitrogen / mole

Now, calculate number of Nitrogen Atoms in 0.150 moles of  Zn(NO₃)₂.
As,
 1 mole of  Zn(NO₃)₂ contained  =  1.20 × 10²⁴ atoms of N
Then,
0.15 mole of  Zn(NO₃)₂ will contain  =  X atoms of N
Solving for X,

                                    X  =  (0.15 mol × 1.20 × 10²⁴ atom) ÷ 1 mol

                                    X  =  1.80 × 10²⁴ Atoms of Nitrogen
Result:
           
So, 0.15 mole of  Zn(NO₃)₂ contains 1.80 × 10²⁴ atoms of Nitrogen.
8 0
3 years ago
The chemical symbol for helium is H
Komok [63]

Answer:No, it is He

Mark me brainlieist

7 0
3 years ago
PLEASE PLEASE HELP ME!! I WILL BRAINLIST YOU!! A 28.0 g sample of N2 is in a rigid 4.50 L container at 32 °C. Calculate the pres
chubhunter [2.5K]

Answer:

P=4184.36 torr

Explanation:

For this problem we can use the idea gas law,

PV=nRT

where P is pressure, V is volume, n is moles of substance, R is the constant, and T is temperature, We will need to manipulate it and a couple values so that we can get our answer in torr. To do this, let's rearrange the equation to solve for P.

P=\frac{nRT}{V}

Next, let's convert T (32) to kelvin. To do this, add 273 to the value.

32+273=305

Next, let's convert 28g of N2 to moles of N2. To do this, divide 28 by the molar mass of N2 (28.02)

\frac{28.0}{28.01} \\=.99 moles of N2

Next, we need to find out what value of R we need to use. Because you want your answer in torr, we will need to use the value of

R=62.36\frac{torr}{mol*K}

Now that we have all of our values, let's plug them into the equation (I'll be excluding units for simplicity but they cancel out to leave units of torr in the answer)

P=\frac{(.99)(62.36)(305)}{4.50}\\P=4184.36

P=4184.36 torr

<em>Very briefly</em>, I don't know what your periodic table looks like, but mine has nitrogen's molar mass as 14.01. If you have a different mass of nitrogen, this pretty drastically impacts the value. For example, if your nitrogen's molar mass was rounded to 14.0 (making N2 28g) then it would be one mole instead of .99 moles, raising the answer to 4228.70 torr. If you have any different values just plug them in in their proper spots. A similar concept applies to the Kelvin conversion.

6 0
3 years ago
What is the oxidation number of chromium in the ionic compound ammonium dichromate (nh4)2cr2o7?
lesya692 [45]
The oxidation number of an element is the number of electrons that are gained or lost by the element to form a chemical bond. 
the net oxidation number of the ion is its charge.
compound (NH₄)₂Cr₂O₇ is made of cation - NH₄⁺ and anion - Cr₂O₇²⁻
oxidation number of ion - -2
(oxidation number of Cr x 2 Cr atoms) +(oxidation number of O x 7 O atoms )= -2
oxidation number of Cr = y
oxidation number of O = -2
(y x 2) + (-2 x 7) = -2
2y - 14 = -2
2y = 12
y  = + 6
therefore oxidation number of Cr is +6 
4 0
4 years ago
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