The completed equations are as follows: 2713Al+42He⟶3015P+10n 13 27 Al + 2 4 He ⟶ 15 30 P + 0 1 n; 23994Pu+42He⟶24296Cm+10n 94 239 Pu + 2 4 He ⟶ 96 242 Cm + 0 1 n; 147N+42He⟶178O+11H 7 14 N

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3 years ago

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Under some circumstances, a star can collapse into an extremely dense object made mostly of neutrons and called a neutron star.

Andrews [41]

Answer:

The question is incomplete however this kind of questions about determinate the angular speed and taking a reference of days rotating the first star.

w=0.11312 rad/s

Explanation:

The situation is about a two star the question is incomplete, miss the time rotate one star so we assume the first star rotated once in 30 days so:

Angular momentum

$P_{m}=I*w$

The inertia

$I=\frac{3}{5}*m*r^2$

The momentum must be conserved so

$P_{m1}=P_{m2}$

$I_{1}*w_{1}=I_{2}*w_{2}$

$\frac{2}{5}*m*r_{1}^2*w_{1}=\frac{2}{5}*m*r_{2}^2*w_{2}$

notice don't have to know the mass or use the density however at the end can determinate

$w_{2}=\frac{r_{1}*w_{1}}{r_{2}}$

Time can determinate the frequency so determinate angular speed of the first star

$w_{1}=2\pi*f_{1}$

$t_{1}=30days*\frac{24hr}{1day}*\frac{60minute}{1hr}*\frac{60s}{1minute}=2592000s$

$f_{1}=\frac{1}{t_{1}}=\frac{1}{2592000}=3.858x10^-7Hz$

$w_{1}=2.424x10^{-6}\frac{rad}{s}$

$w_{2}=\frac{7.0x10^8m}{15x10^3m}*2592000$

$w_{2}=0.11312 rad/s$

4 0

3 years ago