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3 years ago

Which of the following refers to stored energy that an object has due to its height?

Physics

2 answers:

Paul [167]3 years ago

7 0

Answer:

Explanation:

The equation for the gravitational potential energy is mgh. h represents the object's height.

VLD [36.1K]3 years ago

5 0

Answer : D. Gravitational Potential

Gravitational Potential energy =mgh

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g A small object of mass 2.5 g and charge 18 uC is suspended motionless above the ground when immersed in a uniform electric fie

kvasek [131]

Answer: $1361.11\ N/C,\text{upward}$

Explanation:

Given

Mass of particle is $m=2.5\ gm$

Charge of particle is $q=18\ \mu C$

Electrostatic force must balance the weight of the particle

$\lim_{n \to \infty} a_n \Rightarrow mg=qE\\\\\Rightarrow E=\dfrac{2.5\times 9.8\times 10^{-3}}{18\times 10^{-6}}\\\\\Rightarrow E=1361.1\ N/C$

Direction of the electric field is in upward direction such that it opposes the gravity force.

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3 years ago

I help much help on 18!!!

ra1l [238]

I think it's something like electrons don't attract, cuz you know the saying "Opposites attract." Cause electrons are negative... Ahaha... sorry, I don't know the answer.

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3 years ago

A high school physics student claims her muscle car can achieve a constant acceleration of 10 ft/s/s. Her friend develops an acc

Nikolay [14]

Answer: Ф = 17.2657 ≈ 17°

Explanation:

we simply apply ET =0 about the ending of the rod

so In.g.L/2sinФ - In.a.L/2cosФ = 0

g.sinФ - a.cosФ = 0

g.sinФ = a.cosФ

∴ tanФ = a/g

Ф = tan⁻¹ a / g

Ф = tan⁻¹ ( 10 / 32.17405)

Ф = tan⁻¹ 0.31080948777

Ф = 17.2657 ≈ 17°

Therefore the angle of rotation of the rod during this acceleration is 17.2657 ≈ 17°

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3 years ago

What's on the other side of a black hole

bearhunter [10]

Not sure, nobody knows hopefully soon we will know

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4 years ago

Read 2 more answers

If R = 12 cm, M = 520 g, and m = 20 g (below), find the speed of the block after it has descended 50 cm starting from rest. Solv

timofeeve [1]

Answer:

v = 0.84 m/s

Explanation:

given,

R = 12 cm

M (mass of pulley )= 520 g

m (mass of block)= 20 g

s = 50 cm = 0.5 m

using conservation of energy

Potential energy = Kinetic energy

$m g h = \dfrac{1}{2}mv^2 + \dfrac{1}{2}I\omega^2$

$I_{disk}= \dfrac{1}{2}MR^2$ and v = r ω

$m g h = \dfrac{1}{2}mv^2 + \dfrac{1}{2}(\dfrac{1}{2}MR^2)(\dfrac{v}{R})^2$

$m g h = \dfrac{1}{2}mv^2 +\dfrac{1}{4}Mv^2$

$m g h = \dfrac{1}{2}v^2(m +\dfrac{1}{2}M)$

$v=\sqrt{\dfrac{2mgh}{m + 0.5 M}}$

$v=\sqrt{\dfrac{2\times 0.020 \times 9.8 \times 0.5}{0.02 + 0.5\times 0.52}}$

v = √0.7

v = 0.84 m/s

5 0

3 years ago